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Re: x = 0.57y9. If y denotes the thousandth digit in the decimal represent [#permalink]
How is the tenth digit 7? Isn't it 5?

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Re: x = 0.57y9. If y denotes the thousandth digit in the decimal represent [#permalink]
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DelademAnku wrote:
How is the tenth digit 7? Isn't it 5?

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Yes, the tenths digit is 5, not 7. The pervious post has a typo.
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Re: x = 0.57y9. If y denotes the thousandth digit in the decimal represent [#permalink]
Then that means 1. Is sufficient cos rounding to the nearest tenth gives you 0.6 cos 7 is Larger than 5. Or?

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Re: x = 0.57y9. If y denotes the thousandth digit in the decimal represent [#permalink]
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DelademAnku wrote:
x = 0.57y9. If y denotes the thousandth digit in the decimal representation of x above, what digit is y?

(1) If x were rounded to the nearest tenth, the result would be 0.6.

(2) If x were rounded to the nearest hundredth, the result would be 0.58.

Then that means 1. Is sufficient cos rounding to the nearest tenth gives you 0.6 cos 7 is Larger than 5. Or?

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When rounding 0.57y9 to the nearest tenth, the value of y does not affect the result because the hundredths digit 7 is already greater than or equal to 5. Therefore, the tenths digit (5) rounds up to 6. Thus, 0.57y9 rounded to the nearest tenth is 0.6.

Rounding rules

Rounding is simplifying a number to a certain place value. To round the decimal drop the extra decimal places, and if the first dropped digit is 5 or greater, round up the last digit that you keep. If the first dropped digit is 4 or smaller, round down (keep the same) the last digit that you keep.

Example:
5.3485 rounded to the nearest tenth = 5.3, since the dropped 4 is less than 5.
5.3485 rounded to the nearest hundredth = 5.35, since the dropped 8 is greater than 5.
5.3485 rounded to the nearest thousandth = 5.349, since the dropped 5 is equal to 5.
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Re: x = 0.57y9. If y denotes the thousandth digit in the decimal represent [#permalink]
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