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Abhishek009 received 3 Kudos for post Re: 3*3^(1/2)/2^(1/2)*4*3^(1/2)/3.

GiverPostDate
TkevkhishviliRe: 3*3^(1/2)/2^(1/2)*4*3^(1/2)/325-Aug-2023
johnpaulSrRe: 3*3^(1/2)/2^(1/2)*4*3^(1/2)/318-Mar-2023
kuxcarRe: 3*3^(1/2)/2^(1/2)*4*3^(1/2)/313-Mar-2023

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