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Re: $1200 is invested at a given interest rate for two years. [#permalink]
stne wrote:
$1200 is invested at a given interest rate for two years. The difference between the simple 2-year non-compounded return at the end of the two years and an annually compounded return is $132. What is the interest rate?

10%
11%
12%
13%
14%


The formula for difference between SI and CI for two years is given by P*(r/100)^2

P*(r/100)^2 = 132
P = 1200
Solving we get r = 33%

confused!!!!!!!!!!


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Re: $1200 is invested at a given interest rate for two years. [#permalink]
prince00113 wrote:
stne wrote:
$1200 is invested at a given interest rate for two years. The difference between the simple 2-year non-compounded return at the end of the two years and an annually compounded return is $132. What is the interest rate?

10%
11%
12%
13%
14%


The formula for difference between SI and CI for two years is given by P*(r/100)^2

P*(r/100)^2 = 132
P = 1200
Solving we get r = 33%

confused!!!!!!!!!!


Please give Kudos if the reply helped you


We know for the first year SI and CI are the same .
Let for the first year rate be R% and SI be x , this can be written as \(\frac{R}{100}*1200 = x\) (i)

Now for the second year the extra money in CI is because interest is calculated on principal + interest and NOT just the interest.
Hence \(\frac{R}{100}\)*(1200+x) =132 (ii)

Substitute the value of x from (i) in (ii) and after simplification we get
R=10%

Hope this helps .
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Re: $1200 is invested at a given interest rate for two years. [#permalink]
stne wrote:
prince00113 wrote:
stne wrote:
$1200 is invested at a given interest rate for two years. The difference between the simple 2-year non-compounded return at the end of the two years and an annually compounded return is $132. What is the interest rate?

10%
11%
12%
13%
14%


The formula for difference between SI and CI for two years is given by P*(r/100)^2

P*(r/100)^2 = 132
P = 1200
Solving we get r = 33%

confused!!!!!!!!!!


Please give Kudos if the reply helped you


We know for the first year SI and CI are the same .
Let for the first year rate be R% and SI be x , this can be written as \(\frac{R}{100}*1200 = x\) (i)

Now for the second year the extra money in CI is because interest is calculated on principal + interest and NOT just the interest.
Hence \(\frac{R}{100}\)*(1200+x) =132 (ii)

Substitute the value of x from (i) in (ii) and after simplification we get
R=10%

Hope this helps .




CI for 1200$ with 10% interest for 2 years 252$
SI for 1200$ with 10% interest for 2 years 240$

CI-SI = 12$

Hope this clears the doubt

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Re: $1200 is invested at a given interest rate for two years. [#permalink]
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