a, b, c, d, and e are five numbers such that a ≤ b ≤ c ≤ d ≤ e and e - c = 4. A is the average (arithmetic mean) of the five numbers, and M is their median. Is A > M?
We need to check, average (arithmetic mean) > median (M), if a, b, c, d, and e are equidistant or not.
Stat1: e + c = 34
So, e= 19 and c= 15, but no idea about a and b, they can be equidistant or not.
Not sufficientStat2: c = a + 10 or, c-a =10, given, e - c = 4. So we can saw, a, b, c, d, and e are not equidistant. So, definitely, A <M.
Sufficient.So, I think B.