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# a, b, c, d, and e are five numbers such that a b c d e and e -

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Re: a, b, c, d, and e are five numbers such that a b c d e and e - [#permalink]
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TarunKumar1234
a, b, c, d, and e are five numbers such that a ≤ b ≤ c ≤ d ≤ e and e - c = 4. A is the average (arithmetic mean) of the five numbers, and M is their median. Is A > M?

We need to check, average (arithmetic mean) > median (M), if a, b, c, d, and e are equidistant or not.

Stat1: e + c = 34
So, e= 19 and c= 23, but no idea about a and b, they can be equidistant or not. Not sufficient

Stat2: c = a + 10 or, c-a =10, given, e - c = 4. So we can saw, a, b, c, d, and e are not equidistant. So, definitely, A <M. Sufficient.

So, I think B.

Hi TarunKumar1234,

A small correction here (calculation mistake),
From Statement 1, e = 19 and c = 15.

Regards,
Ravish.
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Re: a, b, c, d, and e are five numbers such that a b c d e and e - [#permalink]
Bunuel
a, b, c, d, and e are five numbers such that a ≤ b ≤ c ≤ d ≤ e and e - c = 4. A is the average (arithmetic mean) of the five numbers, and M is their median. Is A > M?

(1) e + c = 34
(2) c = a + 10

Project DS Butler Data Sufficiency (DS3)

Hi Bunuel,

A quick query on this question?
a, b, c, d, and e are five numbers....

Here, number means a whole number or a natural number or an integer or a decimal number or any of these?
Although I can see that this number thing doesn't matter in the final answer and doesn't affect our answer choice, I just want to understand for clarity.
TIA.

Regards,
Ravish.
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Re: a, b, c, d, and e are five numbers such that a b c d e and e - [#permalink]
ravish844
TarunKumar1234
a, b, c, d, and e are five numbers such that a ≤ b ≤ c ≤ d ≤ e and e - c = 4. A is the average (arithmetic mean) of the five numbers, and M is their median. Is A > M?

We need to check, average (arithmetic mean) > median (M), if a, b, c, d, and e are equidistant or not.

Stat1: e + c = 34
So, e= 19 and c= 23, but no idea about a and b, they can be equidistant or not. Not sufficient

Stat2: c = a + 10 or, c-a =10, given, e - c = 4. So we can saw, a, b, c, d, and e are not equidistant. So, definitely, A <M. Sufficient.

So, I think B.

Hi TarunKumar1234,

A small correction here (calculation mistake),
From Statement 1, e = 19 and c = 15.

Regards,
Ravish.

Thanks! It is corrected.
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Re: a, b, c, d, and e are five numbers such that a b c d e and e - [#permalink]
1
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ravish844
Bunuel
a, b, c, d, and e are five numbers such that a ≤ b ≤ c ≤ d ≤ e and e - c = 4. A is the average (arithmetic mean) of the five numbers, and M is their median. Is A > M?

(1) e + c = 34
(2) c = a + 10

Project DS Butler Data Sufficiency (DS3)

Hi Bunuel,

A quick query on this question?
a, b, c, d, and e are five numbers....

Here, number means a whole number or a natural number or an integer or a decimal number or any of these?
Although I can see that this number thing doesn't matter in the final answer and doesn't affect our answer choice, I just want to understand for clarity.
TIA.

Regards,
Ravish.

It means real numbers, so it can be integer, fraction, or an irrational number.
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Re: a, b, c, d, and e are five numbers such that a b c d e and e - [#permalink]
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Re: a, b, c, d, and e are five numbers such that a b c d e and e - [#permalink]
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