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A bag contains 3 white balls, 3 black balls & 2 red balls

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Re: A bag contains 3 white balls, 3 black balls & 2 red balls  [#permalink]

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New post 02 Aug 2015, 05:22
First option (first two balls are not red and the last is red): 6/8*5/7*2/6=5/28

Second option (first or second ball is red and the last is red): (6/8*2/7*1/6)*2=2/28

So, 5/28+2/28=7/28=1/4

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Re: A bag contains 3 white balls, 3 black balls & 2 red balls  [#permalink]

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New post 24 May 2018, 17:00
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: A bag contains 3 white balls, 3 black balls & 2 red balls &nbs [#permalink] 24 May 2018, 17:00
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