A case contains c cartons. Each carton contains b boxes, and

Question

A case contains  c  cartons. Each carton contains  b  boxes, and each box contains 100 paper clips. How many paper clips are contained in 2 cases?

(A) 100bc
(B) 100b/c
(C) 200bc
(D) 200b/c
(E) 200/bc

Bunuel · Accepted Answer

SOLUTION

A case contains  c  cartons. Each carton contains  b  boxes, and each box contains 100 paper clips. How many paper clips are contained in 2 cases?

(A) 100bc
(B) 100b/c
(C) 200bc
(D) 200b/c
(E) 200/bc

Each case contains  100bc  paper clips, hence 2 cases contain  200bc  paper clips.

Answer: C.

ashish8 · Answer

picking numbers

c = 5
b = 2

200 paperclips per carton
200 * 5 = 1000 per case

A. 1000
B. 200/5 = 40
C. 2000
D. 400/5 = 80
E. 20

A.

arthuro69 · Answer

To complete your answer, there are 2 cases so answer (C) is correct.

ashish8 · Answer

Ah yes. Disappointing on my part

PareshGmat · Answer

Case >> Carton >> Box >> Clips

Just multiplication required

Its 2 * (100 * b * c) = 200bc

Answer = C

BrentGMATPrepNow · Answer

Bunuel has already demonstrated an algebraic approach, so let's try solving it by picking some numbers (aka using the INPUT-OUTPUT approach). Let b = 3 and c = 5 So, a case contains 5 cartons. Each carton contains 3 boxes, and each box contains 100 paper clips. So, the number of paper clips in 1 case = (100)( 5 )( 3 ) = 1500 How many paper clips are contained in 2 cases? The number of paper clips in 2 cases = 3000 So, we're looking for the answer choice so that when we INPUT b = 3 and c = 5 , we get an OUTPUT of 3000 Now check the answer choices: (A) 100( 3 )( 5 ) = 1500 ELIMINATE (B) 100( 3 )/( 5 ) = 60 ELIMINATE (C) 200( 3 )( 5 ) = 3000 KEEP!! (D) 200( 3 )/( 5 ) = 120 ELIMINATE (E) 200/( 3 )( 5 ) = 200/15 ELIMINATE Answer: C RELATED RESOURCES As you can see, Bunuel and I have demonstrated the two methods (Algebraic and Input-Output) for solving a question type I call Variables in the Answer Choices. If you'd like more information on these approaches, we have some free videos: - Variables in the Answer Choices - https://www.gmatprepnow.com/module/gmat- ... /video/933 - Tips for the Algebraic Approach - https://www.gmatprepnow.com/module/gmat- ... /video/934 - Tips for the Input-Output Approach - https://www.gmatprepnow.com/module/gmat- ... /video/935 Cheers, Brent

mcelroytutoring · Answer

Attached is a visual that should help.

ScottTargetTestPrep · Answer

Solution:

We are given that a case contains c cartons. Each carton contains b boxes, and each box contains 100 paper clips. Thus we can say the following:

c x b x 100 = 100bc paper clips per case. Thus, 2 cases would contain 2 x 100bc = 200bc paper clips.

The answer is C.

LakerFan24 · Answer

I think you can draw this out (really helped me)

1 case  -->  2 cartons  -->  1 carton = 3 boxes  -->  1 box = 100 pc  
>> From here, there are 300 pc in 3 boxes (AKA 1 carton). Since you have 2 cartons here, in 1 case, you have 600 pc. 
>> You want 2 cases, so you have 1,200 pc.

Plug in A/C w/ variables you defined above :
 c=2 (cartons)
b=3 (boxes)

When you plug in, should give you: 1,200.

C) 200bc --> 200(3)(2) --> 200(6) --> 1,200

FANewJersey · Answer

https://i.imgur.com/xBPksYL.jpg

totaltestprepNick · Answer

C https://www.youtube.com/watch?v=tFX78Po0Dr0 Nick Slavkovich, GMAT/GRE tutor with 20+ years of experience tutoring@totaltestprep.net

A case contains c cartons. Each carton contains b boxes, and

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A case contains c cartons. Each carton contains b boxes, and

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