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A certain CEO drove from his home to a helipad at an average rate of 5

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Bunuel
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A certain CEO drove from his home to a helipad at an average rate of 5 [#permalink] New post   29 Mar 2017, 05:05
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A certain CEO drove from his home to a helipad at an average rate of 50 miles per hour and then boarded a helicopter, which traveled at an average speed of 80 miles per hour, to his office building. If it took the CEO 1.5 hours to reach his office building from home and he spent 4 times as long driving as he did flying, what is the distance from his home to his office building?

A. 84
B. 75
C. 72
D. 60
E. 18
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Re: A certain CEO drove from his home to a helipad at an average rate of 5 [#permalink] New post   29 Mar 2017, 10:58
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Home---50mph----->Helipad---80mph--->Office building


Home----------1.5hrs---------------->Office building


Home---4T-------->Helipad-----T----->Office building


5T = 1.5 hrs
T = 0.3 hrs

Home---1.2hrs---->Helipad-----0.3hrs->Office building

Home---50*1.2 miles----->Helipad---80*0.3 miles--->Office building

Distance from his home to his office building = 60+24 = 84 miles

Answer is A. 84
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Re: A certain CEO drove from his home to a helipad at an average rate of 5 [#permalink] New post   29 Mar 2017, 11:44
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Bunuel wrote:
A certain CEO drove from his home to a helipad at an average rate of 50 miles per hour and then boarded a helicopter, which traveled at an average speed of 80 miles per hour, to his office building. If it took the CEO 1.5 hours to reach his office building from home and he spent 4 times as long driving as he did flying, what is the distance from his home to his office building?

A. 84
B. 75
C. 72
D. 60
E. 18



total time =1.5 hrs = 90 minutes
let time taken to cover helipad to office=x minutes
then time taken from home to helipad =4x
thus 4x+x=90
5x=90
x=18minutes
4x =72 mnutes

distance = speed*time
distance of home to helipad = 50*72/60 = 60miles
distance of helipad to office = 80*18/60 = 24miles
thus total distance = 60+24=84miles

Ans A
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Re: A certain CEO drove from his home to a helipad at an average rate of 5 [#permalink] New post   31 Mar 2017, 12:37
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Bunuel wrote:
A certain CEO drove from his home to a helipad at an average rate of 50 miles per hour and then boarded a helicopter, which traveled at an average speed of 80 miles per hour, to his office building. If it took the CEO 1.5 hours to reach his office building from home and he spent 4 times as long driving as he did flying, what is the distance from his home to his office building?

A. 84
B. 75
C. 72
D. 60
E. 18


We are given that a CEO traveled at a rate of 50 mph when driving and then 80 mph when traveling in a helicopter. Since he traveled for 4 times as long when driving as he did when riding in the helicopter, we can let the time flying = t and the time driving = 4t. Since he spend a total of 1.5 hours traveling, we can create the following equation to determine t:

t + 4t = 1.5

5t = 1.5

t = 1.5/5 = 0.3

Thus, the flying time is 0.3 hour and the driving time 4 x 0.3 = 1.2 hours. Finally, the distance he drove was 50 x 1.2 = 60 miles and the distance he flew was 80 x 0.3 = 24 miles.

So, the total distance is 60 + 24 = 84 miles.

Answer: A
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Re: A certain CEO drove from his home to a helipad at an average rate of 5 [#permalink] New post   02 Apr 2017, 07:09
Bunuel wrote:
A certain CEO drove from his home to a helipad at an average rate of 50 miles per hour and then boarded a helicopter, which traveled at an average speed of 80 miles per hour, to his office building. If it took the CEO 1.5 hours to reach his office building from home and he spent 4 times as long driving as he did flying, what is the distance from his home to his office building?

A. 84
B. 75
C. 72
D. 60
E. 18



Solution:


Total travel time = 1.5 hours
Total driving time = 4 * total flying time.
So Driving time = 4/%*1.5=1.2 hours
Flying time = 0.3 hour

Total distance covered = 1.2 * 50 + 0.3* 80( Speeds of flying and driving given in the question)
= 84 miles

Hence Answer =A.

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Re: A certain CEO drove from his home to a helipad at an average rate of 5 [#permalink] New post   17 Apr 2017, 06:36
Option A

Given: Time taken while driving = 4*Time taken while flying: T = 4t
Total time taken = 4t + t =1.5 hours
t = 0.3 hours

Distance driven = 50*4*0.3 = 60 miles
Distance flown = 80*0.3 = 24 miles

Total = 60 + 24 = 84 miles
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Re: A certain CEO drove from his home to a helipad at an average rate of 5 [#permalink] New post   11 Jan 2024, 23:38
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Re: A certain CEO drove from his home to a helipad at an average rate of 5 [#permalink]
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