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A certain jar contains 60 jelly beans — 22 white, 18 green, 11 yellow,

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A certain jar contains 60 jelly beans — 22 white, 18 green, 11 yellow,  [#permalink]

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New post 12 Jul 2018, 00:31
00:00
A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

82% (01:13) correct 18% (01:15) wrong based on 38 sessions

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A certain jar contains 60 jelly beans — 22 white, 18 green, 11 yellow, 5 red and 4 purple. If a jelly bean is to be chosen at random, what is the probability that the jelly bean will be neither red nor purple?

(A) 0.09
(B) 0.15
(C) 0.54
(D) 0.85
(E) 0.91

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A certain jar contains 60 jelly beans — 22 white, 18 green, 11 yellow,  [#permalink]

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New post Updated on: 12 Jul 2018, 00:55
Total = 60
White = 22
Green = 18
Yellow = 11
Red = 5
Purple = 4

Now,
Neither red nor purple = Either white, green or yellow
Therefore,
P(W or G or Y) = P(W) + P(G) + P(Y)
= 22\60 + 18\ 60 + 11\60
= 51\60
=0.85

Hence, D
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Originally posted by sudarshan22 on 12 Jul 2018, 00:46.
Last edited by sudarshan22 on 12 Jul 2018, 00:55, edited 1 time in total.
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A certain jar contains 60 jelly beans — 22 white, 18 green, 11 yellow,  [#permalink]

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New post 12 Jul 2018, 00:52
A certain jar contains 60 jelly beans — 22 white, 18 green, 11 yellow, 5 red and 4 purple

If a jelly bean is to be chosen at random, the probability that the jelly bean will be neither red nor purple is same as the probability that the jelly bean will be white, green or yellow

Probability = (number of favorable possibilities)/(total number of possibilities)

=> \(P = \frac{(22+18+11)}{60}\)

=> \(\frac{51}{60}\)

=> \(0.85\)

Hence option D
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A certain jar contains 60 jelly beans — 22 white, 18 green, 11 yellow,  [#permalink]

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New post 12 Jul 2018, 03:35
The probability that there will be red or purple: \(\frac{9}{60}\)=\(\frac{3}{20}\)
The probability that there wont be red or purple: 1-\(\frac{3}{20}\)=\(\frac{17}{20}\)=0.85

In My Opinion
Ans: D
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A certain jar contains 60 jelly beans — 22 white, 18 green, 11 yellow, &nbs [#permalink] 12 Jul 2018, 03:35
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