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04 Feb 2018, 21:40
Kudos
Bookmarks
B
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Difficulty:
15%
(low)
Question Stats:
86% (01:35) correct
14%
(01:58)
wrong
based on 81
sessions
History
Date
Time
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Not Attempted Yet
A certain manufacturer has three machines producing the same item. If Machine X produces 1/4 as many of the item as Machine Y produces in the same time, and Machine Y produces twice as many of the item as Machine Z in the same time, then during a fixed period Machine Z produces what fraction of the total number of items produced?
(A) 1/14
(B) 2/7
(C) 1/3
(D) 1/2
(E) 4/7
(A) 1/14
(B) 2/7
(C) 1/3
(D) 1/2
(E) 4/7
04 Feb 2018, 21:48
Kudos
Bookmarks
B
Let the rate of machine X, Y and Z be x, y and z.
We have,
x=y/4
and
y=2z
So total productivity = x+y+z
=y/4+y+z
=2z/4+2z+z
=z/2+3z
=7z/2
Hence total number of items produced = time/rate
=2/7
Let the rate of machine X, Y and Z be x, y and z.
We have,
x=y/4
and
y=2z
So total productivity = x+y+z
=y/4+y+z
=2z/4+2z+z
=z/2+3z
=7z/2
Hence total number of items produced = time/rate
=2/7
04 Feb 2018, 22:10
Kudos
Bookmarks
Bunuel
let the no. of items produced in time t by Y is a
so items produced by x be a/4
items produced by z be a/2
all items produced in time t=a/4+a+a/2=7a/4
fraction of work by z : (a/2)/(7a/4)=2/7
help with kudos if u liked my explaination.TIA
