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zisis
A circle and a square have the same area. What is the ratio of the diameter of the circle to the diagonal of the square?

(A) 2 : √(2π)
(B) 1 : 2√π
(C) 2√π : √2
(D) 1 : √2
(E) 1 : 2π

\(\pi r^2 = a^2\)

\(\frac{r}{a} = \frac{1}{\sqrt{\pi}}\)

\(\frac{2r}{\sqrt{2}a} = \frac{2}{\sqrt{2\pi}}\)

Hence A
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Had to copy and paste (pi). Is there a better way?

Posted from my mobile device
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zisis
Had to copy and paste (pi). Is there a better way?

Posted from my mobile device

Mark \pi by [m] button. Also check: https://gmatclub.com/forum/writing-mathe ... 72468.html

hope it helps.
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What is the ratio of the diameter of the circle to the diagonal of the square - the area of the square and circle is equal?

(A) 2 : √(2pi)
(B) 1 : 2√pi
(C) 2√pi : √2
(D) 1 : √2
(E) 1 : 2(pi)
Diameter be D and diagonal be y then D/Y = ?
given is area of square = area of circle
=> 1/2*Y^2 = 1/4*pi*D^2
=>D/Y= sqrt(2/pi) = 2/sqrt(2pi)

Ans A it is.
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Refer diagram below:

\(\pi r^2 = a^2\)

\(a = \sqrt{\pi}r\)

\(\frac{Diameter of circle}{Diagonal of Square} = \frac{2r}{\sqrt{2} \sqrt{\pi}r}\)

\(Answer = \frac{2}{\sqrt{2 \pi}\) = A
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Answer = A

Let the area of circle = area of square = 1

\(\pi r^2 = 1\)

\(r = \frac{1}{\sqrt{\pi}}\)

2r = diameter \(= \frac{2}{\sqrt{\pi}}\)

Side of square = 1

Diagonal \(= \sqrt{2}\)

Ratio \(= \frac{2}{\sqrt{2*\pi}}\)
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zisis
A circle and a square have the same area. What is the ratio of the diameter of the circle to the diagonal of the square?

(A) \(2 : \sqrt{(2\pi)}\)
(B) \(1 : 2\sqrt{\pi}\)
(C) \(2\sqrt{\pi} : \sqrt{2}\)
(D) \(1 : \sqrt{2}\)
(E) \(1 : 2\pi\)

Let us denote the length of a side of the square by s and the radius of the circle by r.

We can create the equation:

πr^2 = s^2

r√π = s

Since the side of the square s = r√π, the diagonal of the square is r√π x √2 = r√(2π).

The diameter of the circle is 2r. Thus, the ratio of the diameter of the circle to the diagonal of the square is:

2r/[r√(2π)] = 2/√(2π)

Answer: A
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