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Re: A cylinder with a volume of 80π is altered so that its radius becomes [#permalink]
Expert Reply
Bunuel wrote:
A cylinder with a volume of 80π is altered so that its radius becomes half of the original radius and its height becomes double the original height. What is the volume of the altered cylinder?


A. \(160\pi\)

B. \(80\pi\)

C. \(40\pi\)

D. \(20\pi\)

E. \(10\pi\)


We can let r = the original radius and h = the original height of the cylinder. So we have:

πr^2h = 80π

r^2h = 80

Now, we can make up a convenient number for r and calculate h. For example, we can let r = 4, so we have:

4^2h = 80

16h = 80

h = 5

Now, let’s halve the radius and double the height, so the new radius is 2 and the new height is 10. Therefore, the new volume is:

π x 2^2 x 10 = 40π

Answer: C
GMAT Club Bot
Re: A cylinder with a volume of 80π is altered so that its radius becomes [#permalink]
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