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A driver delivered food from a restaurant to a customer’s home by way

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Bunuel
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A driver delivered food from a restaurant to a customer’s home by way [#permalink] New post   18 Mar 2020, 07:52
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84% (00:56) correct 16% (01:22) wrong based on 44 sessions
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A driver delivered food from a restaurant to a customer’s home by way of a certain route. If the driver then completed 20 percent of the return trip by way of the same route before the delivery vehicle broke down, what percent of the round trip did the driver complete?

A. 10%
B. 20%
C. 60%
D. 70%
E. 80%
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C
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Re: A driver delivered food from a restaurant to a customer’s home by way [#permalink] New post   18 Mar 2020, 09:42
Bunuel wrote:
A driver delivered food from a restaurant to a customer’s home by way of a certain route. If the driver then completed 20 percent of the return trip by way of the same route before the delivery vehicle broke down, what percent of the round trip did the driver complete?

A. 10%
B. 20%
C. 60%
D. 70%
E. 80%


let round trip = 10 miles
so half distance = 5miles
and 20% of 5 miles of round ; 1 mile
so total distance covered ; 5+1 ; 6 miles i.e 60%
IMO C
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Re: A driver delivered food from a restaurant to a customer’s home by way [#permalink] New post   20 Mar 2020, 06:57
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Bunuel wrote:
A driver delivered food from a restaurant to a customer’s home by way of a certain route. If the driver then completed 20 percent of the return trip by way of the same route before the delivery vehicle broke down, what percent of the round trip did the driver complete?

A. 10%
B. 20%
C. 60%
D. 70%
E. 80%


Solution:

If the trip each way is 10 miles, then the driver completed 10 miles to the customer’s home and 2 miles on the way back. Thus, the driver completed 12 miles of the 20-mile round trip. Therefore, he completed 12/20 = 3/5 = 60% of the round trip.

Alternate Solution:

When the driver reaches the customer’s house, he has already completed 50% of the trip, and he has 50% remaining. If he breaks down after completing 20% of the 50% remaining, then he has completed an additional 0.2 x 0.5 = 0.1, or 10%, of the round trip. Thus, he has completed 50% + 10% = 60% of the entire round trip when he breaks down.

Answer: C
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Re: A driver delivered food from a restaurant to a customer’s home by way [#permalink] New post   20 Mar 2020, 07:59
Bunuel wrote:
A driver delivered food from a restaurant to a customer’s home by way of a certain route. If the driver then completed 20 percent of the return trip by way of the same route before the delivery vehicle broke down, what percent of the round trip did the driver complete?

A. 10%
B. 20%
C. 60%
D. 70%
E. 80%


Let total trip distance be '2x'

Hence one side distance will be 'x'

Now as per question, driver completed [x + 20% of x] distance of the total trip.

Hence percentage of total trip completed,

=> \(\frac{x+\frac{20}{100} * x}{2x} * 100\)

=> \(\frac{x+\frac{x}{5}}{2x} * 100\)

=> \(\frac{\frac{6x}{5}}{2x} * 100\)

=> \(\frac{6x}{10x} * 100\)

=> 60%

Hence C
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A driver delivered food from a restaurant to a customer’s home by way [#permalink] New post   23 Mar 2020, 03:56
It is easy to want to add 20% to 50%. However, clearly not the answer. Instead, we must determine the amount of the total trip that 20% of the return trip is equal to. The return trip represents 50% of the journey. More difficult problems may not use such an easy number.

20% is also represented as .2, and half of the trip as .5 | Multiply .2*.5 --> =.1, or 10%
Add 10%+50% --> 60%

Answer C
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A driver delivered food from a restaurant to a customer’s home by way [#permalink]
23 Mar 2020, 03:56
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