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A factory that employs 1000 assembly line workers pays each

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gmat620
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A factory that employs 1000 assembly line workers pays each [#permalink] New post   07 Nov 2009, 03:10
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A factory that employs 1000 assembly line workers pays each of these workers $5 per hour for the first 40 hours worked during a week and 1½ times that rate for hours worked in excess of 40. What was the total payroll for the assembly-line workers for a week in which 30 percent of them worked 20 hours, 50 percent worked 40 hours, and the rest worked 50 hours?

(A) $180,000
(B) $185,000
(C) $190,000
(D) $200,000
(E) $205,000
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B
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bimalr9
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Re: A factory that employs 1000 assembly line workers pays each [#permalink] New post   07 Jun 2016, 05:14
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Nadiuska wrote:
Any tip to get this question right in 2 minutes? It took me 4!


I did it in the following way.

\(30/100 * 1000 = 300\)
\(50/100 * 1000 = 500\)
\(20/100 * 1000 = 200\)

Hours are in same digits i.e. 20,40 and 50. Divide the digits by 10 and you will get 2,4, and 5. I reduced the number of employees to 3,5, and 2.
Now,
\(3*2*5 = 30\)
\(5*4*5 = 100\)
\(2*4*5 = 40\)
\(2*1*15/2 = 15\)

If we add them all it will be 185. The answer with 185 is only B.
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kundankshrivastava
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Re: A factory that employs 1000 assembly line workers pays each [#permalink] New post   21 May 2014, 08:16
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30% of 1000 = 300 worked for 20 hours
Payment @ 5/hr
Total Payment = 300*20*5 = 30000

50 % of 1000 = 500 worked for 40 hours
Payment @ 5/hr
Total payment = 500*40*5 = 100000

Remaining 200 worked for 50 Hours

Payment for first 40 Hours @ 5 /hr
Payment = 200*40*5 = 40000
Payment for next 10 hr @ 7.5/hr
Payment = 200 * 10 * 7.5 = 15000

Total Payment = 30000+100000 + 40000 +15000 = 185000

Hence , answer is B
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Re: one from paper test [#permalink] New post   07 Nov 2009, 04:49
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B.
300*5*20 + 500*5*40 + 200*5*40 + 200*7.5*10
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Re: A factory that employs 1000 assembly line workers pays each [#permalink] New post   07 Jun 2016, 07:57
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gmat620 wrote:
A factory that employs 1000 assembly line workers pays each of these workers $5 per hour for the first 40 hours worked during a week and 1½ times that rate for hours worked in excess of 40. What was the total payroll for the assembly-line workers for a week in which 30 percent of them worked 20 hours, 50 percent worked 40 hours, and the rest worked 50 hours?

(A) $180,000
(B) $185,000
(C) $190,000
(D) $200,000
(E) $205,000


30% of 1000 = 300 *20*5= 30000
50% of 1000 = 500 *40 *5= 100000
Remaining 200= 200 *40*5 + 200*10*7.5= 55000

Total= 185,000

B is the answer
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Re: A factory that employs 1000 assembly line workers pays each [#permalink] New post   14 Jul 2018, 19:26
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gmat620 wrote:
A factory that employs 1000 assembly line workers pays each of these workers $5 per hour for the first 40 hours worked during a week and 1½ times that rate for hours worked in excess of 40. What was the total payroll for the assembly-line workers for a week in which 30 percent of them worked 20 hours, 50 percent worked 40 hours, and the rest worked 50 hours?

(A) $180,000
(B) $185,000
(C) $190,000
(D) $200,000
(E) $205,000


So we have 300 workers who worked 20 hours, 500 workers who worked 40 hours, and the remaining 200 workers who worked 50 hours.

For the 300 workers who worked 20 hours, payroll was 300 x (20 x 5) = $30,000.

For the 500 workers who worked 40 hours, payroll was 500 x (40 x 5) = $100,000.

For the 200 workers who worked 50 hours, payroll was 200 x (40 x 5 + 10 x 7.5) = $55,000.

Therefore, the total payroll for all1000 workers is 30,000 + 100,000 + 55,000 = 185,000.

Answer: B
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Re: A factory that employs 1000 assembly line workers pays each [#permalink] New post   25 Sep 2019, 11:48
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workers * wage * hours

First step: 300*5*20
Second step: 500*5*40
Third step: 200*5*40 + 200*7.5*10

\((300*5*20) + (500*5*40) + (200*5*40) + (200*7.5*10)\)

\(10^{3}(30 + 100 + 40 + 15)\)

\(10^{3}(185)\)

\(185,000\)
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Re: A factory that employs 1000 assembly line workers pays each [#permalink] New post   16 Jan 2016, 07:31
Any tip to get this question right in 2 minutes? It took me 4!
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Re: A factory that employs 1000 assembly line workers pays each [#permalink] New post   07 Jun 2016, 05:54
gmat620 wrote:
A factory that employs 1000 assembly line workers pays each of these workers $5 per hour for the first 40 hours worked during a week and 1½ times that rate for hours worked in excess of 40. What was the total payroll for the assembly-line workers for a week in which 30 percent of them worked 20 hours, 50 percent worked 40 hours, and the rest worked 50 hours?

(A) $180,000
(B) $185,000
(C) $190,000
(D) $200,000
(E) $205,000



300 workers: Payment $5 per hour; Total hours worked: 20. Total payment: 30 K
500 workers: Payment $5 per hour; Total hours worked: 40. Total payment: 100 K
200 workers:
Part a) Payment $5 per hour; Total hours worked: 40. Total payment: 40 K
Part b) Payment $7.5 per hour; Total hours worked: 10. Total payment: 15 K

30+100+40+15 = 185 K

B is the answer.
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Re: A factory that employs 1000 assembly line workers pays each [#permalink] New post   07 Jan 2022, 07:38
300*5*20+500*40*5+200*40*5+200*10*7.5=185000
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Re: A factory that employs 1000 assembly line workers pays each [#permalink] New post   18 Apr 2024, 02:50
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Re: A factory that employs 1000 assembly line workers pays each [#permalink]
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