A factory that employs 1000 assembly line workers pays each

Question

A factory that employs 1000 assembly line workers pays each of these workers $5 per hour for the first 40 hours worked during a week and 1½ times that rate for hours worked in excess of 40. What was the total payroll for the assembly-line workers for a week in which 30 percent of them worked 20 hours, 50 percent worked 40 hours, and the rest worked 50 hours?

(A) $180,000
(B) $185,000
(C) $190,000
(D) $200,000
(E) $205,000

(A) $180,000
(B) $185,000
(C) $190,000
(D) $200,000
(E) $205,000

bimalr9 · Accepted Answer

I did it in the following way.

30/100 * 1000 = 300 
 50/100 * 1000 = 500 
 20/100 * 1000 = 200

Hours are in same digits i.e.  20,40 and 50 . Divide the digits by 10 and you will get  2,4, and 5 . I reduced the number of employees to  3,5, and 2 .
Now,
 3*2*5 = 30 
 5*4*5 = 100 
 2*4*5 = 40 
 2*1*15/2 = 15

If we add them all it will be 185. The answer with 185 is only B.

Economist · Answer

B.
300*5*20 + 500*5*40 + 200*5*40 + 200*7.5*10

kundankshrivastava · Answer

30% of 1000 = 300 worked for 20 hours
Payment @ 5/hr 
Total Payment = 300*20*5 = 30000

50 % of 1000 = 500 worked for 40 hours
Payment @ 5/hr
Total payment = 500*40*5 = 100000

Remaining 200 worked for 50 Hours

Payment for first 40 Hours @ 5 /hr
Payment = 200*40*5 = 40000
Payment for next 10 hr @ 7.5/hr
Payment = 200 * 10 * 7.5 = 15000

Total Payment = 30000+100000 + 40000 +15000 = 185000

Hence , answer is B

Nadiuska · Answer

Any tip to get this question right in 2 minutes? It took me 4!

adiagr · Answer

300 workers: Payment $5 per hour; Total hours worked: 20. Total payment: 30 K
500 workers: Payment $5 per hour; Total hours worked: 40. Total payment: 100 K
200 workers: 
 Part a) Payment $5 per hour; Total hours worked: 40. Total payment: 40 K
 Part b) Payment $7.5 per hour; Total hours worked: 10. Total payment: 15 K

30+100+40+15 = 185 K

B is the answer.

Divyadisha · Answer

30% of 1000 = 300 *20*5= 30000
50% of 1000 = 500 *40 *5= 100000
Remaining 200= 200 *40*5 + 200*10*7.5= 55000

Total= 185,000

B is the answer

JeffTargetTestPrep · Answer

So we have 300 workers who worked 20 hours, 500 workers who worked 40 hours, and the remaining 200 workers who worked 50 hours.

For the 300 workers who worked 20 hours, payroll was 300 x (20 x 5) = $30,000.

For the 500 workers who worked 40 hours, payroll was 500 x (40 x 5) = $100,000.

For the 200 workers who worked 50 hours, payroll was 200 x (40 x 5 + 10 x 7.5) = $55,000.

Therefore, the total payroll for all1000 workers is 30,000 + 100,000 + 55,000 = 185,000.

Answer: B

energetics · Answer

workers * wage * hours

First step: 300*5*20 
Second step: 500*5*40
Third step: 200*5*40 + 200*7.5*10

(300*5*20) + (500*5*40) + (200*5*40) + (200*7.5*10)

10^{3}(30 + 100 + 40 + 15)

10^{3}(185)

185,000

naveeng15 · Answer

300*5*20+500*40*5+200*40*5+200*10*7.5=185000

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A factory that employs 1000 assembly line workers pays each

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