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A fivedigit positive integer N has all digits different and contains
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05 Feb 2020, 02:01
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Competition Mode Question A fivedigit positive integer N has all digits different and contains digits 1, 3, 4, 5, and 6 only. If N is the smallest possible number such that it is divisible by 11, then what is the tens digit of N. A. 1 B. 3 C. 4 D. 5 E. 6 Are You Up For the Challenge: 700 Level Questions
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Re: A fivedigit positive integer N has all digits different and contains
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05 Feb 2020, 02:47
divisiblity rule of 11 ; sum of odd place of no = sum of even place of no possible no ; smallest ; 14356 ; IMO d ; 5
A fivedigit positive integer N has all digits different and contains digits 1, 3, 4, 5, and 6 only. If N is the smallest possible number such that it is divisible by 11, then what is the tens digit of N.
A. 1 B. 3 C. 4 D. 5 E. 6



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Re: A fivedigit positive integer N has all digits different and contains
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05 Feb 2020, 03:05
A fivedigit positive integer N has all digits different and contains digits 1, 3, 4, 5, and 6 only. If N is the smallest possible number such that it is divisible by 11, then what is the tens digit of N.
A. 1 B. 3 C. 4 D. 5 E. 6
For a number to be divisible by 11 One's digit + Hundred's digit + Ten Thousand's digit  Ten's digit  Thousandth's digit should be divisible by 11.
Because the subtraction requires to be 2 digit number (11) or 0 > Try to maximize the addition of 3 numbers 0 is not possible since the maximum addition of 2 numbers is 11 and thus rest of the 3 numbers when added equals 8
4+5+613 = 11 is the combination
Since N has to be smallest > N > 41536 > Therefore Ten's digit is 3 > Answer  B



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Re: A fivedigit positive integer N has all digits different and contains
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05 Feb 2020, 05:14
Quote: A fivedigit positive integer N has all digits different and contains digits 1, 3, 4, 5, and 6 only. If N is the smallest possible number such that it is divisible by 11, then what is the tens digit of N.
A. 1 B. 3 C. 4 D. 5 E. 6
N: combination{13456} divisible by 11; A number is div by 11, when: difference between alternating digits is div by 11; in this case, we need to find a difference of 11 or 0. 13456: [1+4+6][3+5]=118=3=invalid 13465: [1+4+5][3+6]=109=1=invalid 41536: [4,5,6][1,3]=154=11=valid Ans (B)



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Re: A fivedigit positive integer N has all digits different and contains
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05 Feb 2020, 06:23
N = abcde N is divisible by 11 => (b+d)  (a+c+e) is divisible by 11 Because (1+3)(4+5+6) is divisible by 11 => The minimum value of N is 41536 => Choice B



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Re: A fivedigit positive integer N has all digits different and contains
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05 Feb 2020, 09:57
A fivedigit positive integer N has all digits different and contains digits 1, 3, 4, 5, and 6 only. If N is the smallest possible number such that it is divisible by 11, then what is the tens digit of N. A. 1 B. 3 C. 4 D. 5 E. 6 A number is divisible by 11 if difference between sum of digits at odd places and sum of digits in even places is either '0' or divisible be 11. Here sum of all digits 1,3,4,5 and 6 is 19. Hence sum of digits at odd places must be '15' and sum of digits at even places must be '4' so that it sums to '19' and differs by '11'. Now 15 is possible for following combinations: 645 456 564 ..... ..... ..... More importantly digits 1 and 3 cant take odd places eventually to sum '15' as 4 can't take even place to sum '4'. Hence N must start with 4. Also, the thousand digit(even place) must be smaller than tens digit so that N is smaller. So, Tens place must be taken by 3. Hence N = 41536 Answer B.
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Re: A fivedigit positive integer N has all digits different and contains
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05 Feb 2020, 18:52
We have to take the difference of alternative digits to check for the divisibility of N.
By trial and error method, the difference can not be be zero and only be +11
So, the set of odd digits and even digits that would satisfy the divisibility rule of 11 is Odd —> {4, 5, 6} & Even —> {1, 3}
The smallest number that can be formed using the above is 41536
Ten’s Digit = 3
Option B
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Re: A fivedigit positive integer N has all digits different and contains
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05 Feb 2020, 19:51
N is divisible by 11 only when the difference between the sum of (tens digit + thousands digit) and the sum of (unit digit + hundred digit + ten thousands digit) is divisible by 11. (found on the internet)
We have: 1. the sum of (tens digit + thousands digit) and the sum of (unit digit + hundred digit + ten thousands digit) = 1+3+4+5+6 =19 2. from the above sum, we can say that the difference between the 2 above sum need to be 0 or 11. But 19 is not divisible by 2, so the difference between the two sum need to be 11.
=> the bigger sum is: (11+19)/2 = 15 and the smaller sum is: (1911)/2 = 4 = 1+3 => the smaller sum must be the sum of (tens digit + thousands digit).
Because the question require the smallest possible value of N => the tens digit must be 3.
=> Answer: B (this question is too evil to me).



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Re: A fivedigit positive integer N has all digits different and contains
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05 Feb 2020, 21:48
From the divisibility rule for 11, either the sum of the even position digits of N must equal to the sum of the odd position digits of N or the difference between the sum of the even position digits and the sum of the odd position digits of N must be divisible by 11. We know that N is formed from the digits 1, 3, 4, 5, and 6 No combination of the sum of at least two of these numbers (even position digits) is equal to the sum of the remaining three numbers (odd position digits). However 4+5+6 = 15 (sum of odd position digits of N) and 1+3=4 (sum of even position digits of N) 154=11 and 11 is divisible by 11. So we are concerned about the even position digits since we are looking for the tens digit which will occupy an even position in a 5 digit number. For the smallest possible value, 1 must occupy the first even position. Hence 3 must be the tens digit.
The answer is B.



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A fivedigit positive integer N has all digits different and contains
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Updated on: 20 Apr 2020, 02:45
Let’s say that N= ABCDE. —> (A+ C+E) —(B+ D )= must be equal to zero or multiple of 11
Now, we have 1,3,4,5,6 for fivedigit integer N —> smallest number should be 41536 ( divisible by 11) —> (4+5+6)—(1+3) = 15–4 = 11 Tens digit of N is 3
The answer is B
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Originally posted by lacktutor on 05 Feb 2020, 23:12.
Last edited by lacktutor on 20 Apr 2020, 02:45, edited 1 time in total.



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Re: A fivedigit positive integer N has all digits different and contains
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06 Feb 2020, 05:44
By trial and error method, the difference can not be zero and only be +11
So, the set of odd digits and even digits that would satisfy the divisibility rule of 11 is Odd are \({4, 5, 6}\) and Even are \({1, 3}\)
The smallest number that can be formed using the above is 41536
Ten’s Digit \(= 3\)
Option B



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Re: A fivedigit positive integer N has all digits different and contains
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09 Feb 2020, 05:18
Bunuel wrote: Competition Mode Question A fivedigit positive integer N has all digits different and contains digits 1, 3, 4, 5, and 6 only. If N is the smallest possible number such that it is divisible by 11, then what is the tens digit of N. A. 1 B. 3 C. 4 D. 5 E. 6 Are You Up For the Challenge: 700 Level QuestionsThe rule for divisibility by 11 is that the difference between the sum of the oddnumbered digits and the sum of the evennumbered digits must be divisible by 11. For a fivedigit integer abcde, this means that (a + c + e)  (b + d) must be divisible by 11. Notice that the sum of the digits of the number is 1 + 3 + 4 + 5 + 6 = 19. Since 19 is odd, the difference between the alternating sums cannot be 0. Thus, if the fivedigit integer is to be divisible by 11, we must have the difference between the alternating sums equal 11 or 11. Notice that 15  4 = 11 and 4  15 = 11 (and 15 + 4 = 19). Thus, we will look for two groups of numbers, sums of which are 15 and 4. The only way to obtain a sum of 4 using the given numbers is 1 + 3 = 4; thus the second and fourth digits of the numbers must be 1 and 3. The remaining three numbers are 4, 5 and 6. The smallest fivedigit integer we can form using the above restrictions is 41,536 (notice that 41,536 is divisible by 11; we get 41536/11 = 3776), and the tens digit of 41,536 is 3. Answer: B
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Re: A fivedigit positive integer N has all digits different and contains
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