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# A man covered a certain distance at some

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Re: A man covered a certain distance at some [#permalink]
dharam44 wrote:
A man covered a certain distance at some speed. Had he moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. The distance (in km) is:
A.35
B.36
C.37
D.40
E. 25

OA:D

Let the initial speed of man be $$x$$ Kmph
Let the initial time taken by man be $$t$$ hours

$$xt=(x+3)(t-\frac{40}{60})$$

$$-\frac{2}{3}x+3t=2$$ .....(1)

$$xt=(x-2)(t+\frac{40}{60})$$

$$\frac{2}{3}x-2t=\frac{4}{3}$$ .....(2)

Adding $$(1)$$ and $$(2)$$, we get

$$t=2+\frac{4}{3}=\frac{10}{3}$$ hours

Putting $$t =\frac{10}{3}$$hours into $$(1)$$, we get

$$-\frac{2}{3}x+3*\frac{10}{3}=2$$

$$x=\frac{2-3*\frac{10}{3}}{-\frac{2}{3}}=\frac{-8}{-\frac{2}{3}}=12$$ Kmph

Distance travelled $$= xt = 12*\frac{10}{3}= 40$$ Kms
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Re: A man covered a certain distance at some [#permalink]
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Re: A man covered a certain distance at some [#permalink]
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