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Re: A man covered a certain distance at some [#permalink]
dharam44 wrote:
A man covered a certain distance at some speed. Had he moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. The distance (in km) is:
A.35
B.36
C.37
D.40
E. 25


OA:D

Let the initial speed of man be \(x\) Kmph
Let the initial time taken by man be \(t\) hours

\(xt=(x+3)(t-\frac{40}{60})\)

\(-\frac{2}{3}x+3t=2\) .....(1)

\(xt=(x-2)(t+\frac{40}{60})\)

\(\frac{2}{3}x-2t=\frac{4}{3}\) .....(2)

Adding \((1)\) and \((2)\), we get

\(t=2+\frac{4}{3}=\frac{10}{3}\) hours

Putting \(t =\frac{10}{3}\)hours into \((1)\), we get

\(-\frac{2}{3}x+3*\frac{10}{3}=2\)

\(x=\frac{2-3*\frac{10}{3}}{-\frac{2}{3}}=\frac{-8}{-\frac{2}{3}}=12\) Kmph

Distance travelled \(= xt = 12*\frac{10}{3}= 40\) Kms
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Re: A man covered a certain distance at some [#permalink]
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Re: A man covered a certain distance at some [#permalink]
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