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Re: A small table has a length of 12 inches and a breadth of b inches. Cub [#permalink]
What does it mean "The maximum side of such cubes is found to be 4 inches"? I guessed it means that every cube has a side of 4 inches. Is it right?
While "The minimum length of side possible for such a square is 48 inches" means that the square obtained with the few tables has a side lenght of 48?

Thanks, I am not english and am afraid I might not have understood the text right, because I find 24 as the answer.
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A small table has a length of 12 inches and a breadth of b inches. Cub [#permalink]
You've correctly understood it.

If b=24, then use can use cubes of length 12 cm to cover the table; hence, your solution contradicts the statement given.





axelr wrote:
What does it mean "The maximum side of such cubes is found to be 4 inches"? I guessed it means that every cube has a side of 4 inches. Is it right?
While "The minimum length of side possible for such a square is 48 inches" means that the square obtained with the few tables has a side lenght of 48?

Thanks, I am not english and am afraid I might not have understood the text right, because I find 24 as the answer.
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Re: A small table has a length of 12 inches and a breadth of b inches. Cub [#permalink]
axelr
See attached image

axelr wrote:
What does it mean "The maximum side of such cubes is found to be 4 inches"? I guessed it means that every cube has a side of 4 inches. Is it right?
While "The minimum length of side possible for such a square is 48 inches" means that the square obtained with the few tables has a side lenght of 48?

Thanks, I am not english and am afraid I might not have understood the text right, because I find 24 as the answer.


Posted from my mobile device
Attachments

File comment: Pic
IMG_20191105_230233862_HDR.jpg
IMG_20191105_230233862_HDR.jpg [ 1.23 MiB | Viewed 5755 times ]

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Re: A small table has a length of 12 inches and a breadth of b inches. Cub [#permalink]
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This is wrong...though you get right answer

Table is not a square first of all.

Cubes are placed on the surface of the table so as to cover the entire surface. The maximum side of such cubes is found to be 4 inches.

This statement implies that b is a multiple of 4. b=4k, where k is not multiple of 3.

a few such tables are arranged to form a square. The minimum length of side possible for such a square is 48 inches

This statement implies that LCM of 12 and b is 48.

12*b/4=48
12*4k/HCF(12,4k)=48

k=4
b=16

Archit3110 wrote:
axelr
See attached image

axelr wrote:
What does it mean "The maximum side of such cubes is found to be 4 inches"? I guessed it means that every cube has a side of 4 inches. Is it right?
While "The minimum length of side possible for such a square is 48 inches" means that the square obtained with the few tables has a side lenght of 48?

Thanks, I am not english and am afraid I might not have understood the text right, because I find 24 as the answer.


Posted from my mobile device

Attachments

Untitled.png
Untitled.png [ 5.27 KiB | Viewed 5700 times ]

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Re: A small table has a length of 12 inches and a breadth of b inches. Cub [#permalink]
nick1816 ; okay i got your point what I did was that I actually formed square shaped table considering 3 equal '4inches' sides i.e 12 each .. and so as to get min length side of 48 ; 16 such table arrangements would be required...

nick1816 wrote:
This is wrong...though you get right answer

Table is not a square first of all.

Cubes are placed on the surface of the table so as to cover the entire surface. The maximum side of such cubes is found to be 4 inches.

This statement implies that b is a multiple of 4. b=4k, where k is not multiple of 3.

a few such tables are arranged to form a square. The minimum length of side possible for such a square is 48 inches

This statement implies that LCM of 12 and b is 48.

12*b/4=48
12*4k/HCF(12,4k)=48

k=4
b=16

Archit3110 wrote:
axelr
See attached image

axelr wrote:
What does it mean "The maximum side of such cubes is found to be 4 inches"? I guessed it means that every cube has a side of 4 inches. Is it right?
While "The minimum length of side possible for such a square is 48 inches" means that the square obtained with the few tables has a side lenght of 48?

Thanks, I am not english and am afraid I might not have understood the text right, because I find 24 as the answer.


Posted from my mobile device
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A small table has a length of 12 inches and a breadth of b inches. Cub [#permalink]
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A small table has a length of 12 inches and a breadth of b inches. Cubes are placed on the surface of the table so as to cover the entire surface. The maximum side of such cubes is found to be 4 inches. Also, a few such tables are arranged to form a square. The minimum length of side possible for such a square is 48 inches. Find b.

A. 8
B. 16
C. 24
D. 32
E. 48



nick1816, Archit3110

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Re: A small table has a length of 12 inches and a breadth of b inches. Cub [#permalink]
nick1816 wrote:
This is wrong...though you get right answer

Table is not a square first of all.

Cubes are placed on the surface of the table so as to cover the entire surface. The maximum side of such cubes is found to be 4 inches.

This statement implies that b is a multiple of 4. b=4k, where k is not multiple of 3.

a few such tables are arranged to form a square. The minimum length of side possible for such a square is 48 inches

This statement implies that LCM of 12 and b is 48.

12*b/4=48
12*4k/HCF(12,4k)=48

k=4
b=16

Archit3110 wrote:
axelr
See attached image

axelr wrote:
What does it mean "The maximum side of such cubes is found to be 4 inches"? I guessed it means that every cube has a side of 4 inches. Is it right?
While "The minimum length of side possible for such a square is 48 inches" means that the square obtained with the few tables has a side lenght of 48?

Thanks, I am not english and am afraid I might not have understood the text right, because I find 24 as the answer.


Posted from my mobile device



Hi, can you please explain where you obtained the equation: 12*4k/HCF(12,4k)=48 ? Thank you!
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Re: A small table has a length of 12 inches and a breadth of b inches. Cub [#permalink]
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dc2880

Product of a and b= LCM(a,b) * HCF(a,b) ........{ true for any 2 positive integers}

12*b = LCM(12,b) * HCF(12*b)

12*b/[HCF(12*b)] = LCM(12,b)
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Re: A small table has a length of 12 inches and a breadth of b inches. Cub [#permalink]
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To understand what the question is asking and the underlying concepts at play, you could start with a couple of simple numbers and see what the conditions ultimately mean for the unknown side B.

Suppose we had a Rectangle with a Length of 6 and a Width of 4.

"cubes are placed on the surface of the table so as to COVER THE ENTIRE surface"

A cube, with each side equal, must be placed side-by-side on the rectangle such that the entire surface area of the rectangle is covered.

then we are told the MAXIMUM SIDE that such a cube could have.

in our made up example (L = 6 and W = 4) what length could we make the cubes such that they would cover the entire surface area?

1: we could have 1-by-1 and have 6 across the length and 4 across the width --- total of 24

2: we could have 2-by-2 and have 3 across the length and 2 across the width --- total of 6

3. could we use 3-by-3 cubes?
we would be able to put TWO 3-by-3 cubes across the length. However, when we put one row of two cubes down across the length, there would only be 1 inch remaining across the width. we could NOT cover the entire surface area with just 3-by-3 cubes.

1 and 2 are COMMON FACTOR of the Length and Width. The MAXIMUM side of such cubes would be 2 inches, where 2 inches is the GREATEST Common Factor of the Length (6) and the Width (4)

Therefore, the statement "the maximum side of such cubes is found to be 4 inches" is essentially telling us the following:

the GREATEST COMMON FACTOR of (12 and b) = 4 (i)

(Part 2 of the question stem)

we then take the 12 - by - B rectangles and lay them down side by side, creating a square. The MINIMUM Length possible of a Square that could be created is 48 inches.

For the Square to be 48 - by - 48 we would have to lay FOUR tables (12 inches) along the Length Side in the 1st Row.

how many we would have to place in each of the columns would depend on the value of B. The B inch width of each table MUST be evenly divisible into 48 inches.

and since 48 inches is the MINIMUM Length possible of such a Square, the statement is essentially telling us the following:

LOWEST COMMON MULTIPLE of (12 ; b) = 48 (ii)

at this point we can use the following Property:

for any two positive integers (X and Y) the following equation will always hold:

LCM (X ; Y) * GCF (X ; Y) = X * Y

at this point we just need to insert (i) and (ii) for the LCM and GCF and the side lengths of the rectangle.

LCM(12 ; b) * GCF (12 ; b) = 12 * b
48 * 4 = 12 * b

b = 16

Answer *B*
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Re: A small table has a length of 12 inches and a breadth of b inches. Cub [#permalink]
This question is one of the BEST question to test application of HCF and LCM. nick1816 method is the best one to solve this question in my opinion.

Another take -

Assuming 'n' number of cubes. The square formed would have the side as 4n. Therefore, Area = 16n^2.

Area is also = 12 x b x n

=> 12bn = 16n^2
=> 12b = 16n
=> b = 4n/3

Also, for min. sq. side = 48, n = 12.

=> b = 4 x 12/3 = 16.
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Re: A small table has a length of 12 inches and a breadth of b inches. Cub [#permalink]
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Re: A small table has a length of 12 inches and a breadth of b inches. Cub [#permalink]
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