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Alice, Bob, Cindy, Dave and Eddie joined a three-person-a-side basketball tournament. In how many ways can be the three starters be chosen?

A. 5 B. 6 C. 8 D. 9 E. 10

The order in which we select the 3 starters does not matter. For example, selecting Alice then Cindy and then Dave to be the starters is the SAME as selecting Cindy then Dave and then Alice to be the starters. Since order does not matter, we can use COMBINATIONS

We can select 3 players from 5 players in 5C3 ways 5C3 = (5)(4)(3)/(3)(2)(1) = 10

Re: Alice, Bob, Cindy, Dave and Eddie joined a three-person-a-side basketb
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24 Aug 2018, 00:52

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The number of ways of choosing the three starters is the number of ways of choosing three people from a set of five people, where order does not matter and repetition is not allowed. The number of possible selections of three starters is: 5C3 = 5C2 = \(\frac{(5*4)}{(1*2)}\) = \(10\).

Therefore, the answer is E. Answer: E
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