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An alloy contains zinc, copper and tin in the ratio 2:3:1 and another 10 Dec 2020, 07:45
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An alloy contains zinc, copper and tin in the ratio 2:3:1 and another contains copper, tin and lead in the ratio 5:4:3. If equal weights of both alloys are melted together to form a third alloy, then the weight of lead per kg in new alloy will be:

A. 1/10 kg
B. 1/8 kg
C. 1/6 kg
D. 1/4 kg
E. 1/2 kg
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B
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Deepakjhamb
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An alloy contains zinc, copper and tin in the ratio 2:3:1 and another 10 Dec 2020, 08:56
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Ans is 1 / 8 as if we mix in equal proportions the % becomes half of combined both

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An alloy contains zinc, copper and tin in the ratio 2:3:1 and another 19 Dec 2020, 03:21
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2+3+1=6 -> 2*6=12
5+4+3=12
In order to have both alloys in same proportion, we need 2 kgs of 1st for every 1kg of 2nd:

Proportion of Lead = (0+3)/(2*6+12)= 3/24= 1/8 => C
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An alloy contains zinc, copper and tin in the ratio 2:3:1 and another 19 Dec 2020, 03:53
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Lets take the LCM of 5, 4, 3, 2, 1 = 60
We can assume that 60 kg of each alloy is mixed to form a new alloy

Weights of elements in Alloy1
Z:C:T = 2:3:1
Weights will be:

Z = 20
C = 30
T = 10

Weights of elements in Alloy2
C:T:L = 5:4:3
Weights will be:

C = 25
T = 20
L = 15

Weight of Lead in alloy3 is 15 and total weight is 120 (60+60)
Weight of lead in per kg of alloy3 = 15/120 = 1/8

Option B
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An alloy contains zinc, copper and tin in the ratio 2:3:1 and another Updated on: 05 Jun 2024, 05:19
Originally posted by CrackverbalGMAT on 19 Dec 2020, 05:56.
Last edited by CrackverbalGMAT on 05 Jun 2024, 05:19, edited 1 time in total.
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SOLUTION:
Refer to the figure attached.
Convert the ratios of the first alloy into 4:6:2 so that the quantities of the alloys are made equal(12 units each).

Thus weight of lead = 3/(12+12) = 3/24 =1/8 kg (Option B)

Hope this helps :thumbsup:
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An alloy contains zinc, copper and tin in the ratio 2:3:1 and another 19 Dec 2020, 07:05
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Quote:
An alloy contains zinc, copper and tin in the ratio 2:3:1 and another contains copper, tin and lead in the ratio 5:4:3. If equal weights of both alloys are melted together to form a third alloy, then the weight of lead per kg in new alloy will be:
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First alloy consists of zinc = 2x, copper = 3x, tin = x, Total = 6x
second alloy consists of: copper = 5y, tin = 4y, led = 3y, total = 12y

as amounts of the two alloys are equal; 6x = 12y
x = 2y

Total amount of third alloy produced = 6x + 12y = 24y [as x = 2y]

Fraction of led out of the total amount produced = 3y/24y = 1/8

B is correct
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An alloy contains zinc, copper and tin in the ratio 2:3:1 and another 07 May 2022, 05:21
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Deepakjhamb
Ans is 1 / 8 as if we mix in equal proportions the % becomes half of combined both

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Deepakjhamb
Can You explain from where are you getting this?
Also why aren't we adding the weight of Lead from both the alloys as 3+2=5/24
I am getting 1/6 as the answer

Thank You
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An alloy contains zinc, copper and tin in the ratio 2:3:1 and another 05 Aug 2026, 04:14
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RajatGMAT777


Deepakjhamb
Can You explain from where are you getting this?
Also why aren't we adding the weight of Lead from both the alloys as 3+2=5/24
I am getting 1/6 as the answer

Thank You
RajatGMAT777
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As we are mixing both alloy in equal proportion(Which means ratio of both alloy in mixture is 1:1), each alloy is 500 gram.

There is no lead in the 1st alloy, that's why we aren't adding the weight.

There is lead in just 2nd alloy, in the ratio of 1:4. and as we know both alloy are mixed in equal quantity(1:1) the lead value get divided by 2. That's why our answer is (1/4) / 2 = 1/8.
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