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An HR Manager has to go through a pile of resumes

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JapinderKaur
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An HR Manager has to go through a pile of resumes [#permalink] New post   20 May 2014, 15:03
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A
B
C
D
E

Difficulty:

55% (hard)

Question Stats:

86% (02:40) correct 14% (04:26) wrong based on 14 sessions
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An HR Manager has to go through a pile of resumes for an advertised vacancy. All the resumes were received through email. The Manager started by printing out 80% of all resumes. He went through 30% of the printed resumes in 2 days. On the 3rd morning, he sought help from a colleague in going through the resumes. Between themselves, they managed to read 60 resumes that day. By the end of the 3rd day, 108 printed resumes were still left unread. How many resumes did the firm receive? Assume that HR Managers read only the resumes that are printed out.

(A) 280
(B) 300
(C) 240
(D) 375
(E) 400

Source: Original Question

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B
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Re: An HR Manager has to go through a pile of resumes [#permalink] New post   20 May 2014, 19:35
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Lets say total resumes received = x

Resumes printed out \(= \frac{80x}{100}\)

30% of printed resumes \(= \frac{80x}{100} * \frac{30}{100} = \frac{24x}{100}\)

Resumes read = 60

Resumes unread = 108

Setting up the equation

\(\frac{80x}{100} = \frac{24x}{100} + 60 + 108\)

x = 300

Answer = B
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Re: An HR Manager has to go through a pile of resumes [#permalink] New post   20 May 2014, 21:38
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Let's take total resume received = x

Resume printed : 80% of received = 0.8x

30% of printed resume = 30% of 0.8x = 0.24x

Resumes left = 0.8x - 0.24x (HR managers read only printed resumes hence total number of resumes to be read is 0.8x)
= 0.56x
After 3rd day , resumes left = 0.56x - 60
Given that, after end of third day, 108 resumes are left, hence

0.56x-60 = 108=> 0.56x=168 => x = 168/0.56 = 300

Hence answer is B
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Re: An HR Manager has to go through a pile of resumes [#permalink] New post   20 May 2014, 15:10

SOLUTION



Let total resumes received be r
So, resumes printed, p = 0.8r

Resumes read in 1st 2 days: 30% of p = 0.3(0.8r) = 0.24r
Resumes read on 3rd day = 60
Printed resumes still left = 108

So, 0.24r+ 60 + 108 = 0.8r
=>168 = 0.56r
=> r= 168/0.56
=> r= 300

Thus the total number of resumes received is 300, which is Option B.
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Re: An HR Manager has to go through a pile of resumes [#permalink] New post   20 May 2014, 21:12
MavenQ wrote:
An HR Manager has to go through a pile of resumes for an advertised vacancy. All the resumes were received through email. The Manager started by printing out 80% of all resumes. He went through 30% of the printed resumes in 2 days. On the 3rd morning, he sought help from a colleague in going through the resumes. Between themselves, they managed to read 60 resumes that day. By the end of the 3rd day, 108 printed resumes were still left unread. How many resumes did the firm receive? Assume that HR Managers read only the resumes that are printed out.

(A) 280
(B) 300
(C) 240
(D) 375
(E) 400

Source: Original Question



Plugging in works here best. We need to find the total no. of resume that the firm received

I started with option C always. If he received 240 resumes he printed 80% or 192 resumes
1st day and 2nd day he read 30% of resumes so about 192*0.3 ~ 57.6 which is not possible.It has to be integer So drop this option

Consider option B here So he 300 resumes,printed 80% so 240, finished reading 30% resumes so 240*0.3 =72 and 3rd day finished 60 more so by the end of 3rd day he finished 72+60=132 and left with 108 -----> Bingo. This is what the questions also says.

Ans is B

I think it is not a good question because normally the answer options should have been either in ascending or descending order.
You may want to reconsider the source from which you are studying.
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Re: An HR Manager has to go through a pile of resumes [#permalink] New post   22 May 2014, 09:10
Faster way:

70 % printed resumes, which Mgr could not read at the end of 2 days = 60+108 = 168
-----> 0.7 *0.8 of x resumes = .56x = 168
-----> x= 168/.56 = 300
Option B.

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Re: An HR Manager has to go through a pile of resumes [#permalink]
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