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Re: An intelligent shopkeeper uses a special weighing balance in which one [#permalink]
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Kudos
Let the weight of the heavier pan be 'x' kgs more than the lighter pan and the cost price of 1 kg of the merchandise be $'p'.
When appearing to buy 1 kg, since he puts the weights on the heavier pan and the merchandise on the lighter one, he actually gets (1+x) kg for $p. That is, buying 1 kg costs him $p/(1+x).
While appearing to sell 1 kg, since he puts the merchandise on the heavier pan and the weights on the lighter one, he actually sells (1-x) kg for $p.
That is, selling 1 kg fetches him $p/(1-x).
Since his overall gain is 50% [i.e. his sales revenue is (3/2) times of cost of goods]:
p/(1-x) = (3/2)*p/(1+x)....> (3/2)*(1-x) = 1+x....> x = (1/5) kg = 200 gms.
ANS: C
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Re: An intelligent shopkeeper uses a special weighing balance in which one [#permalink]
I am not clear with this question .Can anybody please help
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Re: An intelligent shopkeeper uses a special weighing balance in which one [#permalink]
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