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# An operation Ф is defined by the equation x Ф y = x²/4

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Joined: 12 Sep 2015
Posts: 1798

Kudos [?]: 2467 [1], given: 357

An operation Ф is defined by the equation x Ф y = x²/4 [#permalink]

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02 Aug 2017, 11:17
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Question Stats:

75% (02:10) correct 25% (02:52) wrong based on 92 sessions

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An operation Ф is defined by the equation $$x Ф y = \frac{x^2}{4} - xy + y^2$$ for all numbers x and y. What is the value of 186 Ф 91?

A) 1
B) 4
C) 8
D) 16
E) 24

*kudos for all correct solutions
[Reveal] Spoiler: OA

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Brent Hanneson – Founder of gmatprepnow.com

Kudos [?]: 2467 [1], given: 357

Senior Manager
Joined: 24 Apr 2016
Posts: 335

Kudos [?]: 186 [2], given: 48

Re: An operation Ф is defined by the equation x Ф y = x²/4 [#permalink]

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02 Aug 2017, 11:32
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xФy=$$\frac{x^2}{4}−xy+y^2$$ , can be simplified to $$(\frac{x}{2} - y)^ 2$$

So, 186 Ф 91 = $$(\frac{186}{2} - 91)^ 2$$ = $$(93 - 91)^2$$ = $$2^2$$ = 4

Kudos [?]: 186 [2], given: 48

Senior Manager
Joined: 25 Feb 2013
Posts: 425

Kudos [?]: 189 [1], given: 31

Location: India
GPA: 3.82
Re: An operation Ф is defined by the equation x Ф y = x²/4 [#permalink]

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02 Aug 2017, 11:32
1
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GMATPrepNow wrote:
An operation Ф is defined by the equation $$x Ф y = \frac{x^2}{4} - xy + y^2$$ for all numbers x and y. What is the value of 186 Ф 91?

A) 1
B) 4
C) 8
D) 16
E) 24

*kudos for all correct solutions

The expression can be simplified as $$x Ф y = (\frac{x}{2}-y)^2$$
therefore $$= (\frac{186}{2}-91)^2 = 4$$
Option $$B$$

Kudos [?]: 189 [1], given: 31

Director
Joined: 04 Dec 2015
Posts: 696

Kudos [?]: 303 [1], given: 261

Location: India
Concentration: Technology, Strategy
Schools: ISB '19, IIMA , IIMB, XLRI
WE: Information Technology (Consulting)
An operation Ф is defined by the equation x Ф y = x²/4 [#permalink]

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02 Aug 2017, 11:34
1
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1
This post was
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GMATPrepNow wrote:
An operation Ф is defined by the equation $$x Ф y = \frac{x^2}{4} - xy + y^2$$ for all numbers x and y. What is the value of 186 Ф 91?

A) 1
B) 4
C) 8
D) 16
E) 24

*kudos for all correct solutions

$$x$$ $$Ф$$ $$y = \frac{x^2}{4} - xy + y^2$$ $$=> \frac{(x^2 - 4xy + 4y^2)}{4}$$

$$x$$ $$Ф$$ $$y = \frac{(x - 2y)^2}{4}$$

$$186$$ $$Ф$$ $$91 = \frac{(186 - 2*91)^2}{4}$$

$$186$$ $$Ф$$ $$91 = \frac{(186 - 182)^2}{4}$$

$$186$$ $$Ф$$ $$91 = \frac{4^2}{4}$$

$$186$$ $$Ф$$ $$91 = 4$$

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Kudos [?]: 303 [1], given: 261

Manager
Joined: 22 May 2017
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An operation Ф is defined by the equation x Ф y = x²/4 [#permalink]

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02 Aug 2017, 19:31
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Good question to be done mentally

xФy=(x/2−y)^2=(93−91)^2=4

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Kudos [?]: 9 [1], given: 84

SVP
Joined: 12 Sep 2015
Posts: 1798

Kudos [?]: 2467 [0], given: 357

Re: An operation Ф is defined by the equation x Ф y = x²/4 [#permalink]

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03 Aug 2017, 07:40
Expert's post
Top Contributor
1
This post was
BOOKMARKED
GMATPrepNow wrote:
An operation Ф is defined by the equation $$x Ф y = \frac{x^2}{4} - xy + y^2$$ for all numbers x and y. What is the value of 186 Ф 91?

A) 1
B) 4
C) 8
D) 16
E) 24

*kudos for all correct solutions

When we see that the expression x²/4 - xy + y² has two squares (x²/4 = (x/2)² and y² is obviously a square), we should start wondering whether the expression can be factored into the form (something)²

To make this factorization easier to see, let's factor out 1/4 first.
We get: x²/4 - xy + y² = (1/4)(x² - 4xy + 4y²)
= (1/4)(x - 2y)²

Perfect, we can now say that x Ф y = (1/4)(x - 2y)²
So, 186 Ф 91 = (1/4)[186 - 2(91)]²
= (1/4)[186 - 182]²
= (1/4)[4]²
= (1/4)[16]
= 4

[Reveal] Spoiler:
B

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_________________

Brent Hanneson – Founder of gmatprepnow.com

Kudos [?]: 2467 [0], given: 357

Re: An operation Ф is defined by the equation x Ф y = x²/4   [#permalink] 03 Aug 2017, 07:40
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