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# Asking Excellent Questions

Magoosh GMAT Instructor
Joined: 28 Dec 2011
Posts: 4490
Own Kudos [?]: 29037 [2]
Given Kudos: 130
Manager
Joined: 04 Oct 2013
Posts: 127
Own Kudos [?]: 308 [0]
Given Kudos: 55
Location: India
GMAT Date: 05-23-2015
GPA: 3.45
Magoosh GMAT Instructor
Joined: 28 Dec 2011
Posts: 4490
Own Kudos [?]: 29037 [0]
Given Kudos: 130
Manager
Joined: 04 Oct 2013
Posts: 127
Own Kudos [?]: 308 [0]
Given Kudos: 55
Location: India
GMAT Date: 05-23-2015
GPA: 3.45
mikemcgarry
arunspanda
mikemcgarry
If $$x^2 + 8 = 17$$ and $$x^2 - 2x - 15 = 0$$, then $$3x + 23 =$$
(A) 14
(B) 26
(C) 28
(D) 32
(E) 38

The correct answer is the lowest of the five answer choices,

The article is well written.

However, I have a doubt on the example problem.
In the example, x=-3 is the solution. By substituting the value of x as -3, we get 3x+23 = 14.
Whereas I am getting (A) as the solution, the text marked in RED states the answer as (E).
Am I missing anything.
Dear arunspanda,
Yes, in isolation, this was perhaps ambiguous. By "lowest" I did not mean the answer in the lowest position on the list (which would be (E)), but instead, the answer with the lowest numerical values, which of course is (A). This was made clear on the page of the article itself, on the Magoosh blog, because an OE was given on that page. Did you see that?
Mike

The OA provided in the Magoosh blog is very clear.
Thanks.

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