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At a fair, tickets for rides cost 50 cents each. If Tim spen

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fozzzy
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At a fair, tickets for rides cost 50 cents each. If Tim spen [#permalink] New post   11 Sep 2013, 05:20
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At a fair, tickets for rides cost 50 cents each. If Tim spent all the money he had with him for these tickets, how many ride tickets did he buy?

1) If the cost of tickets had been 60 cents, he could have bought exactly 10 tickets, with no money left over.
2) If he had 50 cents more with him, he could have bought exactly 13 tickets, with no money left over.

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What are the equations for each statement?
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D
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Bunuel
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Re: At a fair, tickets for rides cost 50 cents each. If Tim spen [#permalink] New post   11 Sep 2013, 05:25
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At a fair, tickets for rides cost 50 cents each. If Tim spent all the money he had with him for these tickets, how many ride tickets did he buy?

Say Tim had x cents. We should find the value of x/50.

(1) If the cost of tickets had been 60 cents, he could have bought exactly 10 tickets, with no money left over --> x/60=10 --> x=600 cents --> x/50=12. Sufficient.

(2) If he had 50 cents more with him, he could have bought exactly 13 tickets, with no money left over --> (x+50)/50=13 --> x=600 cents --> x/50=12. Sufficient.
Or: 50 cents is for 1 ticket, so without these 50 cents he can buy 1 less, so 12 tickets.

Answer: D.
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Re: At a fair, tickets for rides cost 50 cents each. If Tim spen [#permalink] New post   13 Sep 2013, 08:12
Why are we dividing by 50 in the second equation?
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Re: At a fair, tickets for rides cost 50 cents each. If Tim spen [#permalink] New post   13 Sep 2013, 08:34
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jhonnybravo wrote:
Why are we dividing by 50 in the second equation?


The question asks "how many ride tickets did he buy?" If he had x cents then he bought x/50 tickets.

Does this make sense?
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Re: At a fair, tickets for rides cost 50 cents each. If Tim spen [#permalink] New post   13 Sep 2013, 08:40
Bunuel wrote:

(2) If he had 50 cents more with him, he could have bought exactly 13 tickets, with no money left over --> (x+50)/50=13 --> x=600 cents --> x/50=12. Sufficient.
Or: 50 cents is for 1 ticket, so without these 50 cents he can buy 1 less, so 12 tickets.

Answer: D.


I've understood that equation I'm talking about this one highlighted in red ( x+50) / 50 why divide by 50 over here?
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Re: At a fair, tickets for rides cost 50 cents each. If Tim spen [#permalink] New post   13 Sep 2013, 08:43
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jhonnybravo wrote:
Bunuel wrote:

(2) If he had 50 cents more with him, he could have bought exactly 13 tickets, with no money left over --> (x+50)/50=13 --> x=600 cents --> x/50=12. Sufficient.
Or: 50 cents is for 1 ticket, so without these 50 cents he can buy 1 less, so 12 tickets.

Answer: D.


I've understood that equation I'm talking about this one highlighted in red ( x+50) / 50 why divide by 50 over here?


If he had 50 cents more with him, he would have x+50 cents and since one ticket costs 50 cents, he could have bought exactly (x+50)/50 tickets.
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Re: At a fair, tickets for rides cost 50 cents each. If Tim spen [#permalink] New post   13 Sep 2013, 10:05
fozzzy wrote:
At a fair, tickets for rides cost 50 cents each. If Tim spent all the money he had with him for these tickets, how many ride tickets did he buy?

1) If the cost of tickets had been 60 cents, he could have bought exactly 10 tickets, with no money left over.
2) If he had 50 cents more with him, he could have bought exactly 13 tickets, with no money left over.

Show Spoiler
What are the equations for each statement?


I am not able to see answer options to choose from. Where are they?
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Re: At a fair, tickets for rides cost 50 cents each. If Tim spen [#permalink] New post   13 Sep 2013, 10:08
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vs224 wrote:
fozzzy wrote:
At a fair, tickets for rides cost 50 cents each. If Tim spent all the money he had with him for these tickets, how many ride tickets did he buy?

1) If the cost of tickets had been 60 cents, he could have bought exactly 10 tickets, with no money left over.
2) If he had 50 cents more with him, he could have bought exactly 13 tickets, with no money left over.

Show Spoiler
What are the equations for each statement?


I am not able to see answer options to choose from. Where are they?


This is a data sufficiency question. Options for DS questions are always the same.

The data sufficiency problem consists of a question and two statements, labeled (1) and (2), in which certain data are given. You have to decide whether the data given in the statements are sufficient for answering the question. Using the data given in the statements, plus your knowledge of mathematics and everyday facts (such as the number of days in July or the meaning of the word counterclockwise), you must indicate whether—

A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient to answer the question asked.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient to answer the question asked.
C. BOTH statements (1) and (2) TOGETHER are sufficient to answer the question asked, but NEITHER statement ALONE is sufficient to answer the question asked.
D. EACH statement ALONE is sufficient to answer the question asked.
E. Statements (1) and (2) TOGETHER are NOT sufficient to answer the question asked, and additional data specific to the problem are needed.

Hope this helps.
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Re: At a fair, tickets for rides cost 50 cents each. If Tim spen [#permalink] New post   13 Jan 2018, 01:05
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Re: At a fair, tickets for rides cost 50 cents each. If Tim spen [#permalink]
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