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Bracelets cost p dollars each at a discount store. At a neighboring re

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harish1986
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Bracelets cost p dollars each at a discount store. At a neighboring re [#permalink] New post   14 Sep 2018, 09:18
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Bracelets cost p dollars each at a discount store. At a neighboring retail chain store, the same bracelets cost $1 more each, which means that x dollars will buy 10 more bracelets at the discount store than at the retail chain store. What is the value of x in terms of p?

A. 10(p + 1)
B. 10(p - 1)
C. 10(\(p^2\) + p)
D. 10(\(p^2\) - p)
E. 10(\(p^2\) + p + 1)
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Bracelets cost p dollars each at a discount store. At a neighboring re [#permalink] New post   Updated on: 15 Jul 2020, 10:54
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Discount Store
Price per piece: $p
Total Money: $x
Total Pieces which we can buy = $x / $p = x/p

Retail Chain Store
Price per piece: $(p+1)
Total Money: $x
Total Pieces which we can buy = $x / $(p+1) = x/(p+1)

Given: At discount store we can buy 10 bracelets more as compared to retail store in $x money
=> x/p = x/(p+1) + 10
multiply both sides with p and (p+1) we get
x(p+1) = xp + 10p*(p+1)
x(p+1-p) = 10p(p+1)
x = 10(p^2 + p)

Answer will be C.
Hope it helps!

Originally posted by BrushMyQuant on 14 Sep 2018, 09:36.
Last edited by BrushMyQuant on 15 Jul 2020, 10:54, edited 1 time in total.
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Re: Bracelets cost p dollars each at a discount store. At a neighboring re [#permalink] New post   20 Aug 2019, 08:10
BrushMyQuant wrote:
Discount Store
Price per piece: $p
Total Money: $x
Total Pieces which we can buy = $x / $p = x/p

Retail Chain Store
Price per piece: $(p+1)
Total Money: $x
Total Pieces which we can buy = $x / $(p+1) = x/(p+1)

Given: At discount store we can buy 10 bracelets more as compared to retail store in $x money
=> x/p = x/(p+1) + 10
multiply both sides with p and (p+1) we get
x(p+1) = xp + 10p*(p+1)
x(p+1-p) = 10p(p+1)
x = 10(p^2 + p)

Answer will be C.
Hope it helps!

harish1986 wrote:
Bracelets cost p dollars each at a discount store. At a neighboring retail chain store, the same bracelets cost $1 more each, which means that x dollars will buy 10 more bracelets at the discount store than at the retail chain store. What is the value of x in terms of p?

A. 10(p + 1)
B. 10(p - 1)
C. 10(p^2 + p)
D. 10(p^2 - p)
E. 10(p^2 + p + 1)



Can you please solve this using plugging in

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Re: Bracelets cost p dollars each at a discount store. At a neighboring re [#permalink] New post   21 Aug 2019, 07:48
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LeenaSai
Once I have the equation x/p = x/(p+1) + 10 ...(1)
I can start substituting the answer choices. Now, before i blindly substitute I will analyze the equation i have above. I see that x is divided by p in LHS and (p+1) in RHS and i have an integer(10) on the right hand side. So, i will try to find a term in which x is a multiple of both p and p+1
=> x = something*p*(p+1) = something*(p^2+p) and luckily C is the only choice which has that.
If I was getting 2-3 terms which have p^2 + p then I would have substituted each one of them (one by one) in (1) and checked.
Hope it helps!

BrushMyQuant wrote:
Discount Store
Price per piece: $p
Total Money: $x
Total Pieces which we can buy = $x / $p = x/p

Retail Chain Store
Price per piece: $(p+1)
Total Money: $x
Total Pieces which we can buy = $x / $(p+1) = x/(p+1)

Given: At discount store we can buy 10 bracelets more as compared to retail store in $x money
=> x/p = x/(p+1) + 10
multiply both sides with p and (p+1) we get
x(p+1) = xp + 10p*(p+1)
x(p+1-p) = 10p(p+1)
x = 10(p^2 + p)

Answer will be C.
Hope it helps!

harish1986 wrote:
Bracelets cost p dollars each at a discount store. At a neighboring retail chain store, the same bracelets cost $1 more each, which means that x dollars will buy 10 more bracelets at the discount store than at the retail chain store. What is the value of x in terms of p?

A. 10(p + 1)
B. 10(p - 1)
C. 10(p^2 + p)
D. 10(p^2 - p)
E. 10(p^2 + p + 1)
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Re: Bracelets cost p dollars each at a discount store. At a neighboring re [#permalink] New post   25 Aug 2019, 18:36
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harish1986 wrote:
Bracelets cost p dollars each at a discount store. At a neighboring retail chain store, the same bracelets cost $1 more each, which means that x dollars will buy 10 more bracelets at the discount store than at the retail chain store. What is the value of x in terms of p?

A. 10(p + 1)
B. 10(p - 1)
C. 10(\(p^2\) + p)
D. 10(\(p^2\) - p)
E. 10(\(p^2\) + p + 1)


We see that we can buy x/p bracelets at the discount store and x/(p + 1) bracelets at the retail chain store. We can create the equation:

x/p = x/(p + 1) +10

Multiplying by p(p + 1), we have:

xp + x = xp + 10p^2 + 10p

x = 10p^2 + 10p

x = 10(p^2 + p)

Answer: C
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Re: Bracelets cost p dollars each at a discount store. At a neighboring re [#permalink] New post   06 May 2022, 09:26
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Re: Bracelets cost p dollars each at a discount store. At a neighboring re [#permalink]
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