Discount StorePrice per piece: $p

Total Money: $x

Total Pieces which we can buy = $x / $p = x/p

Retail Chain StorePrice per piece: $(p+1)

Total Money: $x

Total Pieces which we can buy = $x / $(p+1) = x/(p+1)

Given: At discount store we can buy 10 bracelets more as compared to retail store in $x money

=> x/p = x/(p+1) + 10

multiply both sides with p and (p+1) we get

x(p+1) = xp + 10p*(p+1)

x(p+1-p) = 10p(p+1)

x = 10(p^2 + p)

Answer will be C.

Hope it helps!

harish1986 wrote:

Bracelets cost p dollars each at a discount store. At a neighboring retail chain store, the same bracelets cost $1 more each, which means that x dollars will buy 10 more bracelets at the discount store than at the retail chain store. What is the value of x in terms of p?

A. 10(p + 1)

B. 10(p - 1)

C. 10(p^2 + p)

D. 10(p^2 - p)

E. 10(p^2 + p + 1)

_________________

Ankit

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