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Bracelets cost p dollars each at a discount store. At a neighboring re

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Joined: 18 Nov 2013
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Bracelets cost p dollars each at a discount store. At a neighboring re  [#permalink]

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14 Sep 2018, 09:18
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Difficulty:

45% (medium)

Question Stats:

71% (02:17) correct 29% (02:42) wrong based on 24 sessions

Bracelets cost p dollars each at a discount store. At a neighboring retail chain store, the same bracelets cost $1 more each, which means that x dollars will buy 10 more bracelets at the discount store than at the retail chain store. What is the value of x in terms of p? A. 10(p + 1) B. 10(p - 1) C. 10($$p^2$$ + p) D. 10($$p^2$$ - p) E. 10($$p^2$$ + p + 1) GMAT Tutor Status: Tutor - BrushMyQuant Joined: 05 Apr 2011 Posts: 620 Location: India Concentration: Finance, Marketing Schools: XLRI (A) GMAT 1: 700 Q51 V31 GPA: 3 WE: Information Technology (Computer Software) Re: Bracelets cost p dollars each at a discount store. At a neighboring re [#permalink] Show Tags 14 Sep 2018, 09:36 Top Contributor Discount Store Price per piece:$p
Total Money: $x Total Pieces which we can buy =$x / $p = x/p Retail Chain Store Price per piece:$(p+1)
Total Money: $x Total Pieces which we can buy =$x / $(p+1) = x/(p+1) Given: At discount store we can buy 10 bracelets more as compared to retail store in$x money
=> x/p = x/(p+1) + 10
multiply both sides with p and (p+1) we get
x(p+1) = xp + 10p*(p+1)
x(p+1-p) = 10p(p+1)
x = 10(p^2 + p)

Hope it helps!

harish1986 wrote:
Bracelets cost p dollars each at a discount store. At a neighboring retail chain store, the same bracelets cost \$1 more each, which means that x dollars will buy 10 more bracelets at the discount store than at the retail chain store. What is the value of x in terms of p?

A. 10(p + 1)
B. 10(p - 1)
C. 10(p^2 + p)
D. 10(p^2 - p)
E. 10(p^2 + p + 1)

_________________
Re: Bracelets cost p dollars each at a discount store. At a neighboring re   [#permalink] 14 Sep 2018, 09:36
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