Re: Calculating percents rapidly
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05 Mar 2015, 22:31
I guess no one understood the question. I was not asking about the 12% of 80 but rather going the other way around: "x" number when added a certain percent gives you "y" number.
Anyway, I found a clever trick, maybe some of you will find it easier, I will illustrate with an example:
The final price of a sold item is 5000 and the markup by the retailer is 25% of the cost, what is the original cost?
This of course is 5000/1.25 <- which was not my question but rather how do you calculate that number faster.
My way of thinking would be to divide 1 by its parts composed of the % (in this case 0.25).
We can easily see that .25 fits neatly 4 times in 1, so we have 5 parts in total in the denominator (4 in the "1" + 1 in the "0.25"). We can thus divide the 5000 in 5 equal parts, each being 1000.
Finally, we "lose" the part we don't want (which is 1 part or "0.25"), by simply subtracting that part from the 5000, which gives us 4000. Thus, 5000/1.25= 4000.
When dividing by a fraction (i.e. 0.5), we can apply a similar logic:
5000/0.5 <- we have 1 "parts" consisting of 0.5 and need another "part" to get to one. So, we want "2" parts in total... if one part is 5000, two parts is? 5000*2. Thus, 5000/0.5= 10,000.
Anyway, this might seem complicated to some but I find it helpful, specially for problems where an approximation is sufficient and the numbers are very ugly.