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Circular gears P and Q start rotating at the same time at constant speeds. Gear P makes 10 revolutions per minute and Gear Q makes 40 revolutions per minute. ◉ Rate of Gear P = P = 10
◉ Rate of Gear Q = Q = 40
How many seconds after the gears start rotating will gear Q have made exactly 6 more revolutions than gear P ?Let time be t mins
=> Revolutions done by Gear P = Rate of P * t = 10 * t = 10t
=> Revolutions done by Gear Q = Rate of Q * t = 40 * t = 40t
Q makes 6 more revolutions than P
=> 40t = 10t + 6
=> 40t - 10t = 6
=> 30t = 6
=> t = \(\frac{6}{30}\) mins = \(\frac{6}{30}\) * 60 sec = 12 seconds
So,
Answer will be DHope it helps!
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