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During a one day sale, a store sold each sweater of a certain type for

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During a one day sale, a store sold each sweater of a certain type for  [#permalink]

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New post Updated on: 12 Dec 2018, 05:06
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During a one day sale, a store sold each sweater of a certain type for $30 more than the store's cost to purchase each sweater. How many of these sweaters were sold during the sale?

(1) During the sale, the total revenue from the sale of these sweaters was $270.

(2) During the sale, the store sold each of these sweaters at a price that was 50% greater than the store's cost to purchase each sweater.

Originally posted by netcaesar on 01 Feb 2008, 13:14.
Last edited by Bunuel on 12 Dec 2018, 05:06, edited 2 times in total.
Renamed the topic and edited the question.
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Re: During a one day sale, a store sold each sweater of a certain type for  [#permalink]

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New post 08 Sep 2014, 06:03
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WishMasterUA wrote:
During a one day sale, a store sold each sweater of a certain type for $30 more than the store's cost to purchase each sweater. How many of these sweaters were sold during the sale?

(1) During the sale, the total revenue from the sale of these sweaters was $270.

(2) During the sale, the store sold each of these sweaters at a price that was 50% greater than the store's cost to purchase each sweater.


During a one day sale, a store sold each sweater of a certain type for $30 more than the store's cost to purchase each sweater. How many of thses sweaters were sold during the sale?

(1) During the sale, the total revenue from the sale of these sweaters was $270.

(2) During the sale, the store sold each of these sweaters at a price that was 50% greater than the store's cost to purchase each sweater.

Given: \(p=c+30\)

(1) Revenue = price * # of sweaters sold --> \(270=p*n=(c+30)n\). Not sufficient to determine \(n\).

(2) \(p=1.5c=c+30\) --> \(c=60\). Not sufficient.

(1)+(2) \(c=60\) and \(270=(c+30)n=90n\) --> \(n=3\). Sufficient.

Answer: C.
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Re: During a one day sale, a store sold each sweater of a certain type for  [#permalink]

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New post 18 Jun 2011, 08:38
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WishMasterUA wrote:
During a one day sale, a store sold each sweater of a certain type for 30$ more than the store's cost to purchase each sweater. How many of these sweaters were sold during the sale?

1) During the sale, total revenue from of these sweaters was 270$.

2) During the sale, the store sold each of these sweaters at a price that was 50% greater tan the store's cost to purchase each sweater.


S = selling price
C = cost price
\Question tells us S= C+30

st 1 = Selling price * no of sweaters = 270.............. insufficient
st 2 = S = 1.5C
using information from question
1.5 C = C+30
0.5C = 30
C = 60
S =90
but no clue on revenue or number of sweaters sold. ............. insufficient

together 90* no of sweaters = 270
no of sweater = 3
sufficient

hence C
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Re: During a one day sale, a store sold each sweater of a certain type for  [#permalink]

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New post 01 Feb 2008, 14:59
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netcaesar wrote:
During a one day sale, a store sold each sweater of a certain type for $30 more than the store's cost to purchase each sweater. how many of those sweaters were sold during the sale?

1) During the sale the total revenue from sale of these sweaters was $270
2) During the sale, the store sold each of these sweaters at a price that was 50% greater than the store's cost to purchase each sweater.


(C)

Sale price = $30 + Cost price, or
S = $30 + C

1) Insufficient. Each sweater could have been sold for 60 or 230.
If n sweaters were sold, we have n*S = 270

2) Insufficient. 50% greater = $30, hence
or S = 1.5*C
Plugging this in the first equation, we get S = 90, C = 60. But we still don't have n.

Combining (1) & (2): n*90 = 270
or n = 3
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Re: During a one day sale, a store sold each sweater of a certain type for  [#permalink]

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New post 01 Feb 2008, 15:02
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netcaesar wrote:
During a one day sale, a store sold each sweater of a certain type for $30 more than the store's cost to purchase each sweater. how many of those sweaters were sold during the sale?

1) During the sale the total revenue from sale of these sweaters was $270
2) During the sale, the store sold each of these sweaters at a price that was 50% greater than the store's cost to purchase each sweater.


1: revenue = profits - cost. 270$=(x+30)z z is the number of sweaters.

we have two unknowns and only 1 equation insuff.

2: x= cost. x+30=1.5x --> x=60 Thus total price is 90$. Insuff though b/c we dont know the revenue.

Together: 90z=270 --> z=3

C
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Re: During a one day sale, a store sold each sweater of a certain type for  [#permalink]

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New post 29 May 2011, 11:52
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Given: S = C + 30 [S = Sales, c = cost]

(1) NS=270 [N = number of sales]
So, (c + 30) x N = 270, N is unknown, Insufficient.

(2) c+30 = 150%c, C can be calculated from the equation, but we need N=? Insufficient.
C= 60
Considering C
(60+30) x N = 270
N = 3
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Re: During a one day sale, a store sold each sweater of a certain type for  [#permalink]

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New post 23 Oct 2012, 06:23
Could you please explain :
Revenue = price * # of sweaters sold --> . Not sufficient to determine .

here We can consider Revenue is selling price - cost price , Can we ?
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Re: During a one day sale, a store sold each sweater of a certain type for  [#permalink]

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New post 23 Oct 2012, 06:36
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Re: During a one day sale, a store sold each sweater of a certain type for  [#permalink]

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New post 25 Feb 2015, 07:11
Bunuel wrote:
aiming4mba wrote:
I didn't follow this one. could someone explain this?


During a one day sale, a store sold each sweater of a certain type for $30 more than the store's cost to purchase each sweater. How many of thses sweaters were sold during the sale?

(1) During the sale, the total revenue from the sale of these sweaters was $270.

(2) During the sale, the store sold each of these sweaters at a price that was 50% greater than the store's cost to purchase each sweater.

Given: \(p=c+30\)

(1) Revenue = price * # of sweaters sold --> \(270=p*n=(c+30)n\). Not sufficient to determine \(n\).

(2) \(p=1.5c=c+30\) --> \(c=60\). Not sufficient.

(1)+(2) \(c=60\) and \(270=(c+30)n=90n\) --> \(n=3\). Sufficient.

Answer: C.


Dear Bunuel,I follow the below way to answer the above question and I do not know what is the wrong in my way?

we have that (Selling price per unit) - (Cost price per unit) = (Gross profit from one unit)= 30

270= (Selling price per unit - Cost price per unit)*# of sweaters sold

270= 30*# of sweaters sold

So # of sweaters sold = 270/30
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Re: During a one day sale, a store sold each sweater of a certain type for  [#permalink]

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New post 25 Feb 2015, 14:56
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Hi 23a2012,

In your calculation, you're using the PROFIT to determine the number of sweaters sold, but the $270 mentioned in Fact 1 is based on the REVENUE.

The equation is supposed to be:

$270 = (Sale price per sweater)(number of sweaters).

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Re: During a one day sale, a store sold each sweater of a certain type for  [#permalink]

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