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Re: For a positive integer m, [m] is defined to be the remainder when 7m [#permalink]
gmatophobia wrote:
Bunuel wrote:
For a positive integer m, |m| is defined to be the remainder when 7m is divided by 3. If n is a positive integer, which of the following are equal to 1?

I. [3n + 1]
II. [3n]
III. [3n] + 2

A. I only
B. II only
C. I and II only
D. I and III only
E. I, II, and III


I. [3n + 1]

Remainder(\(\frac{7(3n + 1) }{ 3}\))

Remainder(\(\frac{7(3n) + (7) }{ 3}\))

Remainder = 1

II. [3n]

Remainder(\(\frac{7(3n) }{ 3}\))

Remainder(\(\frac{7(3n) }{ 3}\))

Remainder = 1

III. [3n] + 2

Remainder(\(\frac{7(3n+2) }{ 3}\))

Remainder(\(\frac{7(3n+2) }{ 3}\))

Remainder = 2

Hence, Only I (Option A)


What is the difference between your solution of Case 1 and 2? Both Reminders are 1, Kindly elaborate the explanation

Bunuel , Please provide the Official Explanation of this Question
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Re: For a positive integer m, [m] is defined to be the remainder when 7m [#permalink]
I think case 2 should have zero as the remainder, hence only option A.

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Re: For a positive integer m, [m] is defined to be the remainder when 7m [#permalink]
gmatophobia wrote:
Bunuel wrote:
For a positive integer m, |m| is defined to be the remainder when 7m is divided by 3. If n is a positive integer, which of the following are equal to 1?

I. [3n + 1]
II. [3n]
III. [3n] + 2

A. I only
B. II only
C. I and II only
D. I and III only
E. I, II, and III


I. [3n + 1]

Remainder(\(\frac{7(3n + 1) }{ 3}\))

Remainder(\(\frac{7(3n) + (7) }{ 3}\))

Remainder = 1

II. [3n]

Remainder(\(\frac{7(3n) }{ 3}\))

Remainder(\(\frac{7(3n) }{ 3}\))

Remainder = 1

III. [3n] + 2

Remainder(\(\frac{7(3n+2) }{ 3}\))

Remainder(\(\frac{7(3n+2) }{ 3}\))

Remainder = 2

Hence, Only I (Option A)



Shouldn't it be the remainder of II equal to 0?? thanks!
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Re: For a positive integer m, [m] is defined to be the remainder when 7m [#permalink]
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