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Re: For the circle (x-1)^2 + (y+1)^2 = 20 in the xy-plane, what is the are [#permalink]
can someone please explain = Equation of circle is (x−a)2(x−a)2 + (y−b)2(y−b)2 = r2 ??
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Re: For the circle (x-1)^2 + (y+1)^2 = 20 in the xy-plane, what is the are [#permalink]
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nissstheone wrote:
can someone please explain = Equation of circle is (x−a)2(x−a)2 + (y−b)2(y−b)2 = r2 ??




This equation of the circle follows from the Pythagorean theorem applied to any point on the circle: as shown in the diagram above, the radius is the hypotenuse of a right-angled triangle whose other sides are of length x-a and y-b.

If the circle is centered at the origin (0, 0), then the equation simplifies to: \(x^2+y^2=r^2\).

For more on this subject check Coordinate Geometry chapter of Math Book: https://gmatclub.com/forum/math-coordina ... 87652.html
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Re: For the circle (x-1)^2 + (y+1)^2 = 20 in the xy-plane, what is the are [#permalink]
Hello Bunuel, how did you establish that the circle in given problem is centered at origin, as the same is not stated in the problem statement. Also, the equation x^2+Y^2=R^2 is true only for circles with center as origin, isn't it?

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Re: For the circle (x-1)^2 + (y+1)^2 = 20 in the xy-plane, what is the are [#permalink]
omkartadsare wrote:
Hello Bunuel, how did you establish that the circle in given problem is centered at origin, as the same is not stated in the problem statement. Also, the equation x^2+Y^2=R^2 is true only for circles with center as origin, isn't it?

Posted from my mobile device


Yes, I too was thinking about the same point
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Re: For the circle (x-1)^2 + (y+1)^2 = 20 in the xy-plane, what is the are [#permalink]
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