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Group A, which is a set of positive integers, has an average (arithmet

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Group A, which is a set of positive integers, has an average (arithmet  [#permalink]

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Group A, which is a set of positive integers, has an average (arithmetic mean) of 8 while group B, a different set of positive integers, has an average of 10. In which group is the sum of the numbers greater?

(1) The average of all numbers in both groups combined is 8 2/3
(2) The sum of all numbers in both groups is 52

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Re: Group A, which is a set of positive integers, has an average (arithmet  [#permalink]

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New post 30 Sep 2016, 07:19
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duahsolo wrote:
Group A, which is a set of positive integers, has an average (arithmetic mean) of 8 while group B, a different set of positive integers, has an average of 10. In which group is the sum of the numbers greater?

(1) The average of all numbers in both groups combined is 8 2/3
(2) The sum of all numbers in both groups is 52


Answer D.

We are given A = 8 *a and B = 10 * b, where a and b are the number of terms in A and B groups respectively.

Statement 1 : Average is closer to that of A, so A will be having the sum of terms greater. -- SUFFICIENT

Statement 2 : Sum of All terms = 52. or 8a + 10b = 52. Now, number of terms MUST be an integer, so, for a and b to be an integer, only values that satisfies this equation is b=2 and a = 4. Hence, Sufficient.
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Re: Group A, which is a set of positive integers, has an average (arithmet  [#permalink]

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Re: Group A, which is a set of positive integers, has an average (arithmet   [#permalink] 30 Jan 2018, 09:07
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