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Math Revolution GMAT Instructor
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How many 4digit numbers greater than 3,000 have the digits: 1, 3, 5,
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18 Dec 2018, 02:13
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66% (01:36) correct 34% (01:25) wrong based on 87 sessions
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[ Math Revolution GMAT math practice question] How many \(4\)digit numbers greater than \(3,000\) have the digits: \(1, 3, 5,\) and \(7\)? \(A. 6\) \(B. 9\) \(C. 12\) \(D. 15\) \(E. 18\)
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Re: How many 4digit numbers greater than 3,000 have the digits: 1, 3, 5,
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18 Dec 2018, 05:25
MathRevolution wrote: [ Math Revolution GMAT math practice question] How many \(4\)digit numbers greater than \(3,000\) have the digits: \(1, 3, 5,\) and \(7\)? \(A. 6\) \(B. 9\) \(C. 12\) \(D. 15\) \(E. 18\) MathRevolution question does not specify whether digits can be repeated or not ; seems answer is co relating to the latter... since we have 4 digits and >3000 so first digit can be either 3,5,7 only '3' possibilities ; second digit : 3 possibliites ; could be any of third digit 2 option and 4th option 1 so 3*3*2*1 = 18 IMO E
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Re: How many 4digit numbers greater than 3,000 have the digits: 1, 3, 5,
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20 Dec 2018, 02:00
=> We need to count the \(4\)digit numbers with thousands digits \(3, 5\) and \(7\). The number of \(4\)digit numbers beginning with \(3\) is \(6\). The number of \(4\)digit numbers beginning with \(5\) is \(6\). The number of \(4\)digit numbers beginning with \(7\) is \(6\). Thus, the total number of such \(4\)digit numbers is \(18 = 6 + 6 + 6.\) Therefore, the answer is E. Answer: E
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Re: How many 4digit numbers greater than 3,000 have the digits: 1, 3, 5,
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27 Jan 2019, 05:11
chetan2u the question does not specify if the digits are repeating or not First digit can be taken in 3 ways from 3,5,7 Second digit can be selected in 4 ways from 1,3,5,7 Third digit can be selected in 4 ways from 1,3,5,7 Fourth digit can be selected in 4 ways from 1,3,5,7 If it was mentioned the digits cannot be repeating then, First digit can be selected in 3 ways from 3,5,7 Second digit can be selected in 3 ways from remaining numbers Third digit can be selected in 2 ways from remaining numbers Fourth digit can be selected in 1 way Which gives 18, but shouldn't it be mentioned in the question?



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Re: How many 4digit numbers greater than 3,000 have the digits: 1, 3, 5,
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27 Jan 2019, 06:26
Manat wrote: chetan2u the question does not specify if the digits are repeating or not First digit can be taken in 3 ways from 3,5,7 Second digit can be selected in 4 ways from 1,3,5,7 Third digit can be selected in 4 ways from 1,3,5,7 Fourth digit can be selected in 4 ways from 1,3,5,7 If it was mentioned the digits cannot be repeating then, First digit can be selected in 3 ways from 3,5,7 Second digit can be selected in 3 ways from remaining numbers Third digit can be selected in 2 ways from remaining numbers Fourth digit can be selected in 1 way Which gives 18, but shouldn't it be mentioned in the question? Yes, the language could have been slightly better. It could be ' How many 4digit number greater than 3000 can be formed from digits 1, 3, 5 and 7 without repetition. But, by using AND and the kind of wording, I would take it that the intention is to find the numbers containing all the digits 1, 3, 5 and 7.
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Re: How many 4digit numbers greater than 3,000 have the digits: 1, 3, 5,
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27 Jan 2019, 08:59
but its mentioned in question whether repeatation is allowed or not
if repetation is allowed ans would be 192



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Re: How many 4digit numbers greater than 3,000 have the digits: 1, 3, 5,
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02 Mar 2019, 10:09
MathRevolution wrote: [ Math Revolution GMAT math practice question] How many \(4\)digit numbers greater than \(3,000\) have the digits: \(1, 3, 5,\) and \(7\)? \(A. 6\) \(B. 9\) \(C. 12\) \(D. 15\) \(E. 18\) We see that we have 3 options for the thousands digit, 3 for the hundreds digit, 2 for the tens digit and 1 for the units digit. Thus, the total number of options is 3 x 3 x 2 x 1= 18. Answer: E
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Re: How many 4digit numbers greater than 3,000 have the digits: 1, 3, 5,
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02 Mar 2019, 10:09






