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Re: How many 4-digit numbers greater than 3,000 have the digits: 1, 3, 5, [#permalink]
chetan2u the question does not specify if the digits are repeating or not

First digit can be taken in 3 ways from 3,5,7
Second digit can be selected in 4 ways from 1,3,5,7
Third digit can be selected in 4 ways from 1,3,5,7
Fourth digit can be selected in 4 ways from 1,3,5,7

If it was mentioned the digits cannot be repeating then,

First digit can be selected in 3 ways from 3,5,7
Second digit can be selected in 3 ways from remaining numbers
Third digit can be selected in 2 ways from remaining numbers
Fourth digit can be selected in 1 way

Which gives 18, but shouldn't it be mentioned in the question?
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Re: How many 4-digit numbers greater than 3,000 have the digits: 1, 3, 5, [#permalink]
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Manat wrote:
chetan2u the question does not specify if the digits are repeating or not

First digit can be taken in 3 ways from 3,5,7
Second digit can be selected in 4 ways from 1,3,5,7
Third digit can be selected in 4 ways from 1,3,5,7
Fourth digit can be selected in 4 ways from 1,3,5,7

If it was mentioned the digits cannot be repeating then,

First digit can be selected in 3 ways from 3,5,7
Second digit can be selected in 3 ways from remaining numbers
Third digit can be selected in 2 ways from remaining numbers
Fourth digit can be selected in 1 way

Which gives 18, but shouldn't it be mentioned in the question?


Yes, the language could have been slightly better.
It could be ' How many 4-digit number greater than 3000 can be formed from digits 1, 3, 5 and 7 without repetition.

But, by using AND and the kind of wording, I would take it that the intention is to find the numbers containing all the digits 1, 3, 5 and 7.
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Re: How many 4-digit numbers greater than 3,000 have the digits: 1, 3, 5, [#permalink]
but its mentioned in question whether repeatation is allowed or not

if repetation is allowed ans would be 192
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Re: How many 4-digit numbers greater than 3,000 have the digits: 1, 3, 5, [#permalink]
Expert Reply
MathRevolution wrote:
[Math Revolution GMAT math practice question]

How many \(4\)-digit numbers greater than \(3,000\) have the digits: \(1, 3, 5,\) and \(7\)?

\(A. 6\)
\(B. 9\)
\(C. 12\)
\(D. 15\)
\(E. 18\)



We see that we have 3 options for the thousands digit, 3 for the hundreds digit, 2 for the tens digit and 1 for the units digit. Thus, the total number of options is 3 x 3 x 2 x 1= 18.

Answer: E
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Re: How many 4-digit numbers greater than 3,000 have the digits: 1, 3, 5, [#permalink]
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