If -2 < x <= 5, then which of the following MUST be true?

can anybody explain the answer?

If \(-2 < x \leq {5}\), then which of the following MUST be true?

A) \(-1 < x^2 < 16\)

B) \(4 < x^2 \leq {25}\)

C) \(0 \leq {x^2} \leq {16}\)

D) \(0 < x^2 \leq {25}\)

E) \(-4 \leq {x^2} < 36\)

If -2 < x < 5, then which of the following MUST be true?

A) -1 < x² < 16
B) 4 < x² < 25
C) 0 < x² < 16
D) 0 < x² < 25
E) -4 < x² < 36

Kudos for every correct solution.

Vyshak's solutions are great.
Let's examine his second approach.

If -2 < x < 5, then it's possible that x = 5, in which case x² = 25
In other words, it's possible that x² = 25
When we check the answer choices, we see that...
Answer choice A says that x² < 16. In other words, it says that x² cannot equal 25. ELIMINATE A
Answer choice C says that x² < 16. In other words, it says that x² cannot equal 25. ELIMINATE C

Also, if -2 < x < 5, then it's possible that x = 0, in which case x² = 0
In other words, it's possible that x² = 0
When we check the remaining answer choices, we see that...
Answer choice B says that 4 < x². In other words, it says that x² cannot equal 0. ELIMINATE B
Answer choice D says that 0 < x². In other words, it says that x² cannot equal 0. ELIMINATE D

We're left with 1 answer choice...E

Cheers,
Brent

Square of any number can never b negative, answer D is correct.

I could agree with all of you and eliminate abcd but what about e square of any number cannot be negative so how is option e true.

Can anyone tell why option E.

This to me is a simple question that is complicated by GMAT trickery in the way the answer choices are presented. the smallest value for x^2 is 0, and 0 is always greater than -4, so option E still fulfills the demands of the question. It is always true that x^2 is greater than or equal to -4 because it is always greater than -4.

How can E be answer while it include negative numbers and zero also

If \(-2 < x \leq {5}\), then which of the following MUST be true?

A) \(-1 < x^2 < 16\)
B) \(4 < x^2 \leq {25}\)
C) \(0 \leq {x^2} \leq {16}\)
D) \(0 < x^2 \leq {25}\)
E) \(-4 \leq {x^2} < 36\)

Kudos for every correct solution.

How can E be answer while it include negative numbers and zero also

If \(-2 < x \leq {5}\), then which of the following MUST be true?

A) \(-1 < x^2 < 16\)

B) \(4 < x^2 \leq {25}\)

C) \(0 \leq {x^2} \leq {16}\)

D) \(0 < x^2 \leq {25}\)

E) \(-4 \leq {x^2} < 36\)

If \(-2 < x \leq {5}\), then which of the following MUST be true?

A) \(-1 < x^2 < 16\)

B) \(4 < x^2 \leq {25}\)

C) \(0 \leq {x^2} \leq {16}\)

D) \(0 < x^2 \leq {25}\)

E) \(-4 \leq {x^2} < 36\)

I have to disagree with the solution here. E tells us that |x| is less that 6, which could imply x=5.99999 and so on. However the range is fixed from -2 to 5, and x is not necessarily an integer. If it was, I would have agreed with the solution (E).

For me, I choose D.