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If A=0.abc, where a, b, and c are digits of A, is A greater than 2/3?

Is \(A>\frac{2}{3}\)? --> Is \(A>0.666...\)?

(1) a+b>14 --> since a and b are single digits, then the least value of a is 6 and in this case b must be 9 (a+b=6+9=15>14), thus the least value of A is 0.69, so more than 0.666... Sufficient.

(2) b+c>15. Clearly insufficient, since we know nothing about a.

Question: A greater than 2/3? or A greater than 0.6666? This is again a YES or NO, question. Getting either will be fine for the solution.

(1) a+b>14 or a+b>=15 The possible ways for a and b how we can get this is :

a b 6 9 7 8 8 7 9 6

these are the only possible combinations as anything less than 5 will make the other 10, and well anything more then 9 will result in a 10.

anyways, from the above possible values we can see that each is >=0.6666 =>Sufficient

(2) b+c>15

Here, the main digit that we are concerned about is a as that decides if the no is >=0.666 or not even if b=c=9, but a=1, it will be less then 0.6666 or if a=b=c=9 the in that case it will be greater.

Anyway we need some information of A => Not Sufficient.

Ans : A
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Re: If A=0.abc, where a, b, and c are digits of A, is A greater [#permalink]

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26 Jul 2016, 11:32

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