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If A=0.abc, where a, b, and c are digits of A, is A greater [#permalink]
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03 Sep 2012, 01:22
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If A=0.abc, where a, b, and c are digits of A, is A greater than 2/3? (1) a+b>14 (2) b+c>15
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Last edited by Bunuel on 03 Sep 2012, 03:12, edited 2 times in total.
Renamed the topic and edited the question.



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Re: Value after Decimal point. [#permalink]
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03 Sep 2012, 01:37
If A=0.abc, where a, b, and c are digits of A, is A greater than 2/3?Is \(A>\frac{2}{3}\)? > Is \(A>0.666...\)? (1) a+b>14 > since a and b are single digits, then the least value of a is 6 and in this case b must be 9 (a+b=6+9=15>14), thus the least value of A is 0.69, so more than 0.666... Sufficient. (2) b+c>15. Clearly insufficient, since we know nothing about a. Answer: A. Similar questions to practice: thediscreetcharmoftheds12696240.html#p1039662ifx0rstuwhererstandueachrepresentanonzero109735.htmlHope it helps.
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Re: If A=0.abc, where a, b, and c are digits of A, is A greater [#permalink]
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24 Jun 2013, 03:17



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Re: If A=0.abc, where a, b, and c are digits of A, is A greater [#permalink]
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24 Jun 2013, 09:48
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Bunuel wrote: Bumping for review and further discussion*. Get a kudos point for an alternative solution! *New project from GMAT Club!!! Check HEREQuestion: A greater than 2/3? or A greater than 0.6666? This is again a YES or NO, question. Getting either will be fine for the solution. (1) a+b>14 or a+b>=15 The possible ways for a and b how we can get this is : a b 6 9 7 8 8 7 9 6 these are the only possible combinations as anything less than 5 will make the other 10, and well anything more then 9 will result in a 10. anyways, from the above possible values we can see that each is >=0.6666 =>Sufficient (2) b+c>15 Here, the main digit that we are concerned about is a as that decides if the no is >=0.666 or not even if b=c=9, but a=1, it will be less then 0.6666 or if a=b=c=9 the in that case it will be greater. Anyway we need some information of A => Not Sufficient. Ans : A
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Re: If A=0.abc, where a, b, and c are digits of A, is A greater [#permalink]
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Re: If A=0.abc, where a, b, and c are digits of A, is A greater [#permalink]
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27 Jul 2016, 04:20
shrey2287 wrote: If A=0.abc, where a, b, and c are digits of A, is A greater than 2/3?
(1) a+b>14 (2) b+c>15 (1) a+b>14 let a+b=15 also 10+5 9+6 8+7 6+9 lowest possible value for a = 6 therefore, let A =0.690=690/1000 > 2/3 since lowest possible is > 2/3 Sufficient (2) b+c>15 here a can take 1 or a 9 A=0.199 < 2/3 but A=0.999 > 2/3 insufficient A



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Re: If A=0.abc, where a, b, and c are digits of A, is A greater [#permalink]
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27 Jul 2016, 17:56
shrey2287 wrote: If A=0.abc, where a, b, and c are digits of A, is A greater than 2/3?
(1) a+b>14 (2) b+c>15 Question A>2/3 or .667 1) a+b>14 The minimum possible value for a+b can be 15 lets see the minimum possible value of ab. keeping maximum value of b will give minimum value of a b = 9, hence a=6. these values make the expression as .69c, which is >.667 Sufficient. (2) b+c>15 b+c= 16 (suppose) as in option 1, let's take maximum value for c i.e 9 and minimum value for b i.e 7. But a can be anything from 1 to 9, making .abc > or <2/3 Not Sufficient. A is the answer
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Re: If A=0.abc, where a, b, and c are digits of A, is A greater
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