GMATPrepNow wrote:
If b > 0 and ax < bx < by, is xy > 0?
(1) a – b > 0
(2) a < y
Target question: Is xy > 0? Given: b > 0 and ax < bx < by Since we're told that a - b is POSITIVE, we can take bx < by, and divide both sides by b to get:
x < y Statement 1: a – b > 0 I can see (a - b) "hiding" in the inequality ax < bx, so let's look into this further.
Take ax < bx and subtract bx from both sides to get: ax - bx < 0
Factor: x(a - b) < 0
Since we're told that a - b is POSITIVE, we can divide both sides by a-b to get:
x < 0So,
x is NEGATIVEAlso, a - b > 0, we can add b to both sides to get
a > bIs this enough information to answer the
target question?
Well, we still don't know anything about y, so it seems unlikely that statement 1 is sufficient.
Let's TEST some numbers.
Here are two cases that both that satisfy statement 1:
Case a: a = 3, b = 2, x = -1 and y = 1. In this case, xy = -1.
So, xy < 0Case b: a = 3, b = 2, x = -1 and y = -0.5. In this case, xy = 0.5.
So, xy > 0Since we cannot answer the
target question with certainty, statement 1 is NOT SUFFICIENT
Statement 2: a < y There are several scenarios that satisfy statement 2. Here are two:
Case a: a = 3, b = 10, x = 2 and y = 4. In this case, xy = 8.
So, xy > 0Case b: a = 2, b = 1, x = -1 and y = 10. In this case, xy = -10.
So, xy < 0Since we cannot answer the
target question with certainty, statement 2 is NOT SUFFICIENT
Statements 1 and 2 combined Statement 1 tells us that
x is NEGATIVE and that
b < aSince it's given that 0 < b, we can write:
x < 0 < b < a Statement 2 tells us that
a < yIf we add that information to the above inequality, we get:
x < 0 < b < a < y In other words, x is NEGATIVE and y is POSITIVE, which means
xy < 0Since we can answer the
target question with certainty, the combined statements are SUFFICIENT
Answer: C
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