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If f(a, b) = a2b4, and f(m, n) = 5, what is the value of f(3m, 2n)? [#permalink]
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Solution


Given:
    • f(a, b) = \(a^2b^4\)
    • f(m, n) = 5

To find:
    • The value of f(3m, 2n)

Approach and Working:
    • Given f(a, b) = \(a^2b^4\)
    • So, f(m, n) = \(m^2n^4 = 5\)
    • Now, f(3m, 2n) =\((3m)^2 * (2n)^4 = 3^2 * 2^4 * m^2n^4 = 9 * 16 * 5 = 720\)

Hence, the correct answer is Option D


Answer: D
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Re: If f(a, b) = a2b4, and f(m, n) = 5, what is the value of f(3m, 2n)? [#permalink]
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Given that \(f(a, b) = a^2b^4\), and \(f(m, n) = 5\) and we need to find the value of f(3m, 2n)

To find f(m, n) we need to compare what is inside the bracket in f(m, n) and f(a,b)

=> We need to substitute a with m and b with n in \(f(a, b) = a^2b^4\) to get the value of f(m, n)

=> \(f(m, n) = m^2n^4\) = 5 given

Similarly, \(f(3m, 2n) = (3m)^2(2n)^4\) = \(3^2 * m^2 *2^4 *n^4\) = 9*16 * \(m^2n^4\) = 9*16*5 = 720

So, Answer will be D
Hope it helps!

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Re: If f(a, b) = a2b4, and f(m, n) = 5, what is the value of f(3m, 2n)? [#permalink]
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Re: If f(a, b) = a2b4, and f(m, n) = 5, what is the value of f(3m, 2n)? [#permalink]
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