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If for any number N, f(N) is defined as the least integer
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08 Nov 2012, 06:32
08 Nov 2012, 06:32
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Difficulty:
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Question Stats:
72% (01:03) correct
28%
(01:10)
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based on 236
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If for any number N, f(N) is defined as the least integer that is greater than or equal to N^2, then f(-1.1) =
(A) -2
(B) -1
(C) 0
(D) 1
(E) 2
(A) -2
(B) -1
(C) 0
(D) 1
(E) 2
Re: If for any number N, f(N) is defined as the least integer
[#permalink]
08 Nov 2012, 07:15
08 Nov 2012, 07:15
3
Kudos
Expert Reply
derekgmat wrote:
If for any number N, f(N) is defined as the least integer that is greater than or equal to N^2, then f(-1.1) =
(A) -2
(B) -1
(C) 0
(D) 1
(E) 2
(A) -2
(B) -1
(C) 0
(D) 1
(E) 2
If N=-1.1, then N^2=1.21.
The least integer that is greater than or equal to 1.21 is 2, thus f(-1.1) = 2.
Answer: E.
Hope it's clear.
Re: If for any number N, f(N) is defined as the least integer
[#permalink]
08 Nov 2012, 07:17
08 Nov 2012, 07:17
Expert Reply
derekgmat wrote:
If for any number N, f(N) is defined as the least integer that is greater than or equal to N^2, then f(-1.1) =
(A) -2
(B) -1
(C) 0
(D) 1
(E) 2
(A) -2
(B) -1
(C) 0
(D) 1
(E) 2
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Hope it helps.
