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Statement A: Tells you that k is somewhere between 5 and 6. Based on the definition of the question stem /k/ is thus 5, which is not evently divisible by 2.

=> Sufficient

Statement B:Tells you that the following inequality has to hold: 7 < k + 2.3 < 8 => 4.7 < k < 5.7 => /k/ has to equal 5, which is not evenly divisible.

=> Sufficient

Hence, solution D is correct.
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Can somebody please explain me what '//' symbol implies over here??
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Can somebody please explain me what '//' symbol implies over here??

Stem defines some function, represented by the symbol \(////\), as the function which rounds down any number to an integer value:

\(//3.4//=3\), \(//2//=2\), \(//-7.5//=-8\), ...

Check similar question for practice: https://gmatclub.com/forum/how-x-become ... 94687.html

Hope it helps.
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hmmmmmm........... :idea:

much clear now....thanks!!
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Can somebody explain to me why statement B //k + 2.3// = 7 become this 8 > k + 2.3 >= 7 ?

I am confused ... :?
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Can somebody explain to me why statement B //k + 2.3// = 7 become this 8 > k + 2.3 >= 7 ?

I am confused ... :?

The function rounds down any number to an integer value:

\(//3.4//=3\), \(//2//=2\), \(//-7.5//=-8\), ...

So, //x// = 7, means that 7 <= x < 8. Any number from this range when rounded down gives 7.

Check other Rounding Functions Questions in our Special Questions Directory.
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Bunuel
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Source: Knewton

For all numbers t, let //t// be defined as the greatest integer less than or equal to t. Is //k// evenly divisible by 2?

a) 5 < k < 6
b) //k + 2.3// = 7

Solution to follow...interested to see how people interrupt this question.


Can somebody please explain me what '//' symbol implies over here??

-----------------------------------------------------------------
Consider KUDOS if you like my post!

Stem defines some function, represented by the symbol \(////\), as the function which rounds down any number to an integer value:

\(//3.4//=3\), \(//2//=2\), \(//-7.5//=-8\), ...

Check similar question for practice: how-x-become-fraction-if-its-been-said-an-integer-94687.html

Hope it helps.

7 < k + 2.3 < 8
I'm confuse how they got this
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Bunuel


Stem defines some function, represented by the symbol \(////\), as the function which rounds down any number to an integer value:

\(//3.4//=3\), \(//2//=2\), \(//-7.5//=-8\), ...

Check similar question for practice: how-x-become-fraction-if-its-been-said-an-integer-94687.html

Hope it helps.

7 < k + 2.3 < 8
I'm confuse how they got this

The function rounds down any number to an integer value:

\(//3.4//=3\), \(//2//=2\), \(//-7.5//=-8\), ...

So, //x// = 7, means that 7 <= x < 8. Any number from this range when rounded down gives 7.

Check other Rounding Functions Questions in our Special Questions Directory.
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Bunuel , I didn't get why B is not sufficient . Could you please explain.

So, //x// = 7, means that 7 <= x < 8. Any number from this range when rounded down gives 7.

When any number in this range rounds down to 7 , then

//k+2.3//=7

7<=k+2.3<8

4.7<=k<5.7

So K will rounds down either 4 or 5 . Right . That is what you mean ??

That's why B not sufficient ?

Thanks
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parvgugnani
Bunuel , I didn't get why B is not sufficient . Could you please explain.

So, //x// = 7, means that 7 <= x < 8. Any number from this range when rounded down gives 7.

When any number in this range rounds down to 7 , then

//k+2.3//=7

7<=k+2.3<8

4.7<=k<5.7

So K will rounds down either 4 or 5 . Right . That is what you mean ??

That's why B not sufficient ?

Thanks
Regards

Yes, you have understood the logic perfectly..
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Can somebody explain to me why statement B //k + 2.3// = 7 become this 8 > k + 2.3 >= 7 ?

I am confused ... :?

The function rounds down any number to an integer value:

\(//3.4//=3\), \(//2//=2\), \(//-7.5//=-8\), ...

So, //x// = 7, means that 7 <= x < 8. Any number from this range when rounded down gives 7.

Check other Rounding Functions Questions in our Special Questions Directory.

Hi Bunuel VeritasKarishma

can we not do this like this:

//k + 2.3// = 7

=> //k// +//2.3// = 7
=> //k// + 2= 7
=> //k// = 5
therefore //k// isnt divisble by 2. Whats wrong in this?
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Kritisood
Bunuel
shelrod007
Can somebody explain to me why statement B //k + 2.3// = 7 become this 8 > k + 2.3 >= 7 ?

I am confused ... :?

The function rounds down any number to an integer value:

\(//3.4//=3\), \(//2//=2\), \(//-7.5//=-8\), ...

So, //x// = 7, means that 7 <= x < 8. Any number from this range when rounded down gives 7.

Check other Rounding Functions Questions in our Special Questions Directory.

Hi Bunuel VeritasKarishma

can we not do this like this:

//k + 2.3// = 7

=> //k// +//2.3// = 7
=> //k// + 2= 7
=> //k// = 5
therefore //k// isnt divisble by 2. Whats wrong in this?

With functions, it is not necessary that
f(a+b) = f(a) + f(b)

For example, if the function is defined as f(x) = x^2, then
(a + b)^2 is not equal to a^2 + b^2

So you cannot say //a + b// = //a// + //b//

Also, if //x// = 7, in what range can the value of x lie? x can be anything from 7 to less than 8 because //7// = 7
//7.34// = 7
//7.987685// = 7
and so on...

So 7 <= k + 2.3 < 8

Hope this helps.
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Hi Sir,

Can you explain me how it will 4.7 in statement 2
vaibhavtripathi


S1: 5< k < 6 means //k// = 5. Not divisible by 2. Sufficient.
S2: //k+2.3// = 7 means 8 > k+2.3 >= 7. therefore 5.7 > k >=4.7 and //k// = 4 or 5. Not Sufficient.

Answer: A
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adipisciet
Hi Sir,

Can you explain me how it will 4.7 in statement 2


Because if //k + 2.3// = 7, then k + 2.3 must be at least 7 but less than 8.

So:
7 ≤ k + 2.3 < 8

Subtract 2.3 from all sides:
4.7 ≤ k < 5.7
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