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If m and n are positive integers, is root (n-m) an integer?

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Re: If m and n are positive integers, is root (n-m) an integer? [#permalink]
This is a Yes-No DS question. Start by using plugging in for such questions.

m,n --> Positive integers Is √(n−m) an integer?

1) n > m + 15
n - m > 15

n - m = 16 Answer to the question [Is √(n−m) an integer?] -- Yes
n - m = 17 Answer to the question [Is √(n−m) an integer?] -- No

Insufficient

2) n = m(m+1)

m = 1, n = 2 => √(n−m) = 1 Answer to the question [Is √(n−m) an integer?] -- Yes
m = 2, n = 6 => √(n−m) = 2 Answer to the question [Is √(n−m) an integer?] -- Yes
m = 3, n = 12 => √(n−m) = 3 Answer to the question [Is √(n−m) an integer?] -- Yes
m = 6, n = 42 => √(n−m) = 6 Answer to the question [Is √(n−m) an integer?] -- Yes

Sufficient

Thus, the answer to the question is B.

Hope that helped! Point to remember - Keep Math simple. Don't complicate it! Plugging In can be a really helpful tool in some of the superficially complicated questions.
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Re: If m and n are positive integers, is root (n-m) an integer? [#permalink]
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Re: If m and n are positive integers, is root (n-m) an integer? [#permalink]
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