Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

If \(v>0\) then when dividing by \(v\) we would have: \(m<p<0\); If \(v<0\) then when dividing by \(v\) we would have: \(m>p>0\) (flip the sign when dividing by negative value).

(1) m < p --> we have the first case, so \(v>0\). Sufficient. (2) m < 0 --> we have the first case, so \(v>0\). Sufficient.

You can solve such questions easily by re-stating '< 0' as 'negative' and '> 0' as 'positive'.

mv < pv < 0 implies both 'pv' and 'mv' are negative and mv is more negative i.e. has greater absolute value as compared to pv. Since v will be equal in both, m will have a greater absolute value as compared to p.

When will mv and pv both be negative? In 2 cases: Case 1: When v is positive and m and p are both negative. Case 2: When v is negative and m and p are both positive.

So how will we know whether v is positive? If we know that at least one of m and p is negative, then v must be positive. If at least one of m and p is positive, then v must be negative.

Now that we understand the question and the implications of the given data, we go on to the statements.

Stmnt 1: m < p m has greater absolute value as compared to p but it is still smaller than p. This means m must be negative. If m is negative, p must be negative too which implies that v must be positive. Sufficient.

Stmnt 2: m < 0 Very straight forward. m and p both must be negative and v must be positive. Sufficient.

Ask yourself: if m=3 and p=5 and v is negative, say -1, does mv < pv< 0 hold true?

Aha!! I get it now. So, when m=3, p=5 and v is -ve, mv (-3) becomes > pv (-5) making the given condition void.

So, Stmt 1 is sufficient. Great learning for the day. (This makes me wanna repeat to myself - When you pick numbers, quickly plug in to see if they are correct)

I also figured this just now:

mv < pv < 0 (mv-pv) <0 v(m-p)<0

If v is +ve, m<p (This is what the Statement 1 is saying too) If v is -ve, m>p

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

(1) means both m and p are negative, so in order \(mv\) and \(pv\) to be < 0, \(v\) must be greater than zero. (If it's -ve mv will > 0) (2) same is in (1) m<0 means \(m\) is -ve, and in order mv to be negative v must be greater than zero. Answer D
_________________

When you’re up, your friends know who you are. When you’re down, you know who your friends are.

Share some Kudos, if my posts help you. Thank you !

Statement 1) m < p I tried plugging numbers : m=-3, p=-2 to satisfy (a) consider different values of v : v is positive : v=5 , (-3)(5) < (-2)(5) < 0 = -15 < -10 < 0 ----- satisfy (a) v is negative : v=-5 , (-3)(-5) < (-2)(-5) < 0 = 15 < 10 < 0 ----- does not satisfy (a) Hence, v must be positive

Statement 2) m < 0 from (a) , we can see that mv < 0 hence to satisfy mv < 0 when m < 0 , we need a positive value of v [(-ve)*(+ve)=(-ve)] Therefore v must be positive

Could someone (@Bunuel) please check this alternative approach?

Rephrase stem to \(mv-pv<0\) --> \(v(m-p)<0\)

Stm 1: \(m<p\) --> \(m-p<0\), so \(v\) has to be positive for the above inequality to hold true. Sufficient.

Stm 2: Now this is where i screwed it up since i focused on my rephrased inequality and completely ignored the given one. Is there a way to draw the right conclusion from this inequality \(v(m-p)<0\) in combination with the constraint \(m<0\) of stm 2?

Otherwise i have to adjust my approach for those kind of questions since i tought rephrasing the question stem would in most cases help to evaluate both statements. Probably in this case it made things more complicated...

Version 8.1 of the WordPress for Android app is now available, with some great enhancements to publishing: background media uploading. Adding images to a post or page? Now...

Post today is short and sweet for my MBA batchmates! We survived Foundations term, and tomorrow's the start of our Term 1! I'm sharing my pre-MBA notes...

“Keep your head down, and work hard. Don’t attract any attention. You should be grateful to be here.” Why do we keep quiet? Being an immigrant is a constant...