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If n = (6 4p)^2, then n is at its smallest value when p=

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Bunuel
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If n = (6 4p)^2, then n is at its smallest value when p= [#permalink] If n = (6 4p)^2, then n is at its smallest value when p=   15 Jun 2023, 01:30
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If \(n = (6 − 4p)^2\), then n is at its smallest value when p =

A. –2
B. –1.5
C. 0
D. 1.5
E. 2




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D
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Re: If n = (6 4p)^2, then n is at its smallest value when p= [#permalink] If n = (6 4p)^2, then n is at its smallest value when p=   15 Jun 2023, 01:43
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To solve this question one if is the best way to put the values from options ,Lets p = 1.5
n = (6-4*1.5)^2
n = (6-6)^2
n = 0,
Answer is option [D].
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Re: If n = (6 4p)^2, then n is at its smallest value when p= [#permalink] If n = (6 4p)^2, then n is at its smallest value when p=   15 Jun 2023, 01:54
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n = Square of something…..hence the smallest of n is Zero.

Put n= 0

6-4p = 0

p = 1.5 (d is the answer).

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Re: If n = (6 4p)^2, then n is at its smallest value when p= [#permalink] If n = (6 4p)^2, then n is at its smallest value when p=   15 Jun 2023, 06:27
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Since RHS is a square, n can't be negative. So, the smallest value for n has to be 0. We get this only when p=0 in 6-4p, so Option D- 0.
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Re: If n = (6 4p)^2, then n is at its smallest value when p= [#permalink] If n = (6 4p)^2, then n is at its smallest value when p=   19 Jun 2023, 05:42
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The question stem states that n is the square of a number. Therefore, we know that n is either Zero or Positive.

The smallest possible value of 'n' would therefore be 0.

n = (6-4p)^2.

6 - 4p would result to 0 when the value of p = 1.5 Ans. D.
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Re: If n = (6 4p)^2, then n is at its smallest value when p= [#permalink]
19 Jun 2023, 05:42
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