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Bunuel
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this is a must question:

A. p/q
can be a non-integer

B. pq
always even

C. 2p+q
2p = even -> even+odd = odd

D. 2(p+q)
always even - p+q = odd *2 -> even

E. 3p/q
might be a non integer.

C
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Option C

p = Even, q = Odd. Odd: O, Even: E & Fraction: F

A. p/q = E/O = E or F
B. pq = E*O = E
C. 2p+q = 2E + O = O
D. 2(p+q) = 2(E+O) = E
E. 3p/q = 3(E/O) = 3E or 3F
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Hi All,

If you know the Number Properties involved in this question, then you can get to the correct answer relatively easily. You can also TEST VALUES to get to the answer.

We're told that P is an EVEN integer and Q is an ODD integer. We're asked which of the following must be an ODD integer...

IF....
P = 2 AND Q = 1, then...

Answer A: 2/1 = 2 NOT an odd
Answer B: 2(1) = 2 NOT an odd
Answer C: 2(2) + 1 = 5 This IS an odd
Answer D: 2(2+1) = 6 NOT an odd
Answer E: 3(2)/1 = 6 NOT an odd

Final Answer:
GMAT assassins aren't born, they're made,
Rich
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Bunuel
If p is an even integer and q is an odd integer, which of the following must be an odd integer?

A. p/q
B. pq
C. 2p+q
D. 2(p+q)
E. 3p/q

There are three ways to get an odd integer: odd x odd = odd OR odd/odd = odd OR even + odd = odd. Let’s examine our answer choices to determine which must produce an odd integer.

A) p/q

Since p is even and q is odd, p/q will never be an odd integer.

B) pq

Again, since p is even and q is odd, p/q will never be an odd integer.

C) 2p+q

Since 2p is even and q is odd, 2p + q WILL BE an odd integer.

Answer: C
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