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If # represents one of the operations +, and *, is a #
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If # represents one of the operations +, and *, is a # (bc) = (a#b) – (a#c) for all numbers a, b and c. (1) a#1 is not equal to 1#a for some numbers a (2) # represents subtraction
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Originally posted by zisis on 19 Sep 2010, 15:49.
Last edited by zisis on 19 Sep 2010, 16:09, edited 1 time in total.



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Re: If # represents one of the operations +, and *, is a #
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19 Sep 2010, 15:58
I converted question to 3 euqations where # can be +,  or * So I) When # = * abac = abac (true for all values) II) When # = + Is a+bc=bc III) When #= Is ab+c = bc? With option A we know # is not * as 1*a is always equal to a*1. So given equation is not equal With option B , equation is not equal. So answer choice D
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Re: If # represents one of the operations +, and *, is a #
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19 Sep 2010, 16:50
zisis wrote: If # represents one of the operations +, and *, is a # (bc) = (a#b) – (a#c) for all numbers a, b and c.
(1) a#1 is not equal to 1#a for some numbers a
(2) # represents subtraction
Mods, please to DS section...posted by mistake in PS  apologies 1. From choice 1 it is clear that # is subtraction. coz a+1=1+1, a*1=1*a but a1!=(not equal) 1a. 2. Choice 2 says directly that it is subtraction. Hence answer is D
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Re: If # represents one of the operations +, and *, is a #
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19 Sep 2010, 19:38
vigneshpandi wrote: zisis wrote: If # represents one of the operations +, and *, is a # (bc) = (a#b) – (a#c) for all numbers a, b and c.
(1) a#1 is not equal to 1#a for some numbers a
(2) # represents subtraction
Mods, please to DS section...posted by mistake in PS  apologies 1. From choice 1 it is clear that # is subtraction. coz a+1=1+1, a*1=1*a but a1!=(not equal) 1a. 2. Choice 2 says directly that it is subtraction. Hence answer is D IMO, it cannot be "not equal" always. If # is subtraction, a#(bc)=a(bc)=ab+c (a#b)(a#c)=(ab)(ac)=aba+c=b+c ab+c=b+c when a=0 and not equal for other values.. So both are insufficient.. Am I missing something here?
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Re: If # represents one of the operations +, and *, is a #
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20 Sep 2010, 00:14
BalakumaranP wrote: IMO, it cannot be "not equal" always.
If # is subtraction,
a#(bc)=a(bc)=ab+c
(a#b)(a#c)=(ab)(ac)=aba+c=b+c
ab+c=b+c when a=0 and not equal for other values.. So both are insufficient.. Am I missing something here? If # represents one of the operations +,  and *, is \(a#(bc)=(a#b)(a#c)\) for all numbers \(a\), \(b\) and \(c\). (1) \(a#1\) is not equal to \(1#a\) for some numbers \(a\). \(#\) is neither addition (as \(a+1=1+a\)) not multiplication (as \(a*1=1*a\)), so \(#\) is a subtraction. Then \(LHS=a#(bc)=ab+c\) and \(RHS=(a#b)(a#c)=(ab)(ac)=cb\), so the question becomes "is \(ab+c=cb\) for all numbers \(a\), \(b\) and \(c\)?" > "is \(a=0\)". So when \(a=0\) (and \(#\) is a subtraction) then \(a#(bc)=(a#b)(a#c)\) holds true but not for other values of \(a\), so not for all numbers \(a\), \(b\) and \(c\). Answer to the question is NO. Sufficient. (2) \(#\) represents subtraction > the same as above. Sufficient. Answer: D. Hope it's clear.
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Re: If # represents one of the operations +, and *, is a #
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20 Sep 2010, 03:09
Okay.. I read the question wrong...
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Re: If # represents one of the operations +, and *, is a #
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20 Sep 2010, 19:10
(1) a#1 is not equal to 1#a for some numbers a
a + 1 = 1 + a for all a a*1 = 1*a for all a
a  1 != 1  a
Statement (1) implies # is a minus sign, so it has same meaning as (2).
Ans D



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Re: If # represents one of the operations +, and *, is a #
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21 Sep 2010, 10:55
zisis wrote: If # represents one of the operations +, and *, is a # (bc) = (a#b) – (a#c) for all numbers a, b and c.
(1) a#1 is not equal to 1#a for some numbers a
(2) # represents subtraction
Mods, please to DS section...posted by mistake in PS  apologies You're told that "#" is either addition, subtraction, or multiplication, and then asked if "#" satisfies the distributive property. Of these three, distribution only holds for multiplication, so if "#" is "*", it holds, and if "#" isn't "*", then it does not hold. All we really need to know is what operation "#" really is. (1) This is only true of subtraction, so # is subtraction and the distributive property does not hold. Sufficient. (2) Same as above. Sufficient. (D)



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Re: If # represents one of the operations +, and *, is a #
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03 Jun 2015, 08:54
zisis wrote: If # represents one of the operations +, and *, is a # (bc) = (a#b) – (a#c) for all numbers a, b and c.
(1) a#1 is not equal to 1#a for some numbers a
(2) # represents subtraction Could someone edit this question so it will be an actual question? There is no proper question stem.
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Re: If # represents one of the operations +, and *, is a #
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03 Jun 2015, 08:58



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Re: If # represents one of the operations +, and *, is a #
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03 Jun 2015, 09:07
Bunuel wrote: reto wrote: zisis wrote: If # represents one of the operations +, and *, is a # (bc) = (a#b) – (a#c) for all numbers a, b and c.
(1) a#1 is not equal to 1#a for some numbers a
(2) # represents subtraction Could someone edit this question so it will be an actual question? There is no proper question stem. What do you mean? Everything is correct there. Similar questions: Operations/functions defining algebraic/arithmetic expressionsCheck functions related questions in our Special Questions Directory. Symbols Representing Arithmetic OperationRounding FunctionsVarious FunctionsThe question mark is missing in the question stem.
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Re: If # represents one of the operations +, and *, is a #
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17 Aug 2017, 19:22
Bunuel wrote: BalakumaranP wrote: IMO, it cannot be "not equal" always.
If # is subtraction,
a#(bc)=a(bc)=ab+c
(a#b)(a#c)=(ab)(ac)=aba+c=b+c
ab+c=b+c when a=0 and not equal for other values.. So both are insufficient.. Am I missing something here? If # represents one of the operations +,  and *, is \(a#(bc)=(a#b)(a#c)\) for all numbers \(a\), \(b\) and \(c\). (1) \(a#1\) is not equal to \(1#a\) for some numbers \(a\). \(#\) is neither addition (as \(a+1=1+a\)) not multiplication (as \(a*1=1*a\)), so \(#\) is a subtraction. Then \(LHS=a#(bc)=ab+c\) and \(RHS=(a#b)(a#c)=(ab)(ac)=cb\), so the question becomes "is \(ab+c=cb\) for all numbers \(a\), \(b\) and \(c\)?" > "is \(a=0\)". So when \(a=0\) (and \(#\) is a subtraction) then \(a#(bc)=(a#b)(a#c)\) holds true but not for other values of \(a\), so not for all numbers \(a\), \(b\) and \(c\). Answer to the question is NO. Sufficient. (2) \(#\) represents subtraction > the same as above. Sufficient. Answer: D. Hope it's clear. I don't understand why the answer is not E. if a = 0, then yes, if a is not equal to 0, then no. So not sufficient, as nothing can be said conclusively ... anybody out there to help me ....? thanks



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Re: If # represents one of the operations +, and *, is a #
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17 Aug 2017, 21:24
gmatcracker2017 wrote: Bunuel wrote: BalakumaranP wrote: IMO, it cannot be "not equal" always.
If # is subtraction,
a#(bc)=a(bc)=ab+c
(a#b)(a#c)=(ab)(ac)=aba+c=b+c
ab+c=b+c when a=0 and not equal for other values.. So both are insufficient.. Am I missing something here? If # represents one of the operations +,  and *, is \(a#(bc)=(a#b)(a#c)\) for all numbers \(a\), \(b\) and \(c\). (1) \(a#1\) is not equal to \(1#a\) for some numbers \(a\). \(#\) is neither addition (as \(a+1=1+a\)) not multiplication (as \(a*1=1*a\)), so \(#\) is a subtraction. Then \(LHS=a#(bc)=ab+c\) and \(RHS=(a#b)(a#c)=(ab)(ac)=cb\), so the question becomes "is \(ab+c=cb\) for all numbers \(a\), \(b\) and \(c\)?" > "is \(a=0\)". So when \(a=0\) (and \(#\) is a subtraction) then \(a#(bc)=(a#b)(a#c)\) holds true but not for other values of \(a\), so not for all numbers \(a\), \(b\) and \(c\). Answer to the question is NO. Sufficient. (2) \(#\) represents subtraction > the same as above. Sufficient. Answer: D. Hope it's clear. I don't understand why the answer is not E. if a = 0, then yes, if a is not equal to 0, then no. So not sufficient, as nothing can be said conclusively ... anybody out there to help me ....? thanks The question asks: is \(a#(bc)=(a#b)(a#c)\) for all numbers \(a\), \(b\) and \(c\)? From each statement we got a deinite NO answer  NO the equation doe NOT hold true for all numbers, it's true if a = 0 but not true if a is not 0.
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Re: If # represents one of the operations +, and *, is a #
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17 Aug 2017, 22:01
gmatcracker2017 wrote: Bunuel wrote: BalakumaranP wrote: IMO, it cannot be "not equal" always.
If # is subtraction,
a#(bc)=a(bc)=ab+c
(a#b)(a#c)=(ab)(ac)=aba+c=b+c
ab+c=b+c when a=0 and not equal for other values.. So both are insufficient.. Am I missing something here? If # represents one of the operations +,  and *, is \(a#(bc)=(a#b)(a#c)\) for all numbers \(a\), \(b\) and \(c\). (1) \(a#1\) is not equal to \(1#a\) for some numbers \(a\). \(#\) is neither addition (as \(a+1=1+a\)) not multiplication (as \(a*1=1*a\)), so \(#\) is a subtraction. Then \(LHS=a#(bc)=ab+c\) and \(RHS=(a#b)(a#c)=(ab)(ac)=cb\), so the question becomes "is \(ab+c=cb\) for all numbers \(a\), \(b\) and \(c\)?" > "is \(a=0\)". So when \(a=0\) (and \(#\) is a subtraction) then \(a#(bc)=(a#b)(a#c)\) holds true but not for other values of \(a\), so not for all numbers \(a\), \(b\) and \(c\). Answer to the question is NO. Sufficient. (2) \(#\) represents subtraction > the same as above. Sufficient. Answer: D. Hope it's clear. I don't understand why the answer is not E. if a = 0, then yes, if a is not equal to 0, then no. So not sufficient, as nothing can be said conclusively ... anybody out there to help me ....? thanks Thanks Bunuel, you are soooo... great ....



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Re: If # represents one of the operations +, and *, is a #
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14 Sep 2017, 15:09
Key word in A > 'not equal to'  thus the only time a#1 not 1#a is when # = minus Really need to read questions properly!



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Re: If # represents one of the operations +, and *, is a #
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14 Sep 2017, 15:10
Key word in A > 'not equal to'  thus the only time a#1 not 1#a is when # = minus Really need to read questions properly!




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