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If tank X contains only gasoline, how many kiloliters of gasoline are
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08 Jul 2018, 23:40
08 Jul 2018, 23:40
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If tank X contains only gasoline, how many kiloliters of gasoline are in tank X.
(1) If 1/2 of the gasoline in tank X were pumped out, the tank would be fillef to 1/3 of its capacity.
(2) If .75 kiloliter of gasoline were pumped into tank X, it would be filled to capacity.
(1) If 1/2 of the gasoline in tank X were pumped out, the tank would be fillef to 1/3 of its capacity.
(2) If .75 kiloliter of gasoline were pumped into tank X, it would be filled to capacity.
Re: If tank X contains only gasoline, how many kiloliters of gasoline are
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09 Jul 2018, 00:06
09 Jul 2018, 00:06
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If tank X contains only gasoline, how many kiloliters of gasoline are in tank X.
(1) If 1/2 of the gasoline in tank X were pumped out, the tank would be filled to 1/3 of its capacity.
The values given are % of the total capacity and NO numeric value is given so insufficient
If \(\frac{1}{2}\) is pumped out, HALF will remain so \(\frac{1}{2} = \frac{1}{3}- of -Total\)
so present volume is \(2*\frac{1}{3} = \frac{2}{3}\)
but no numeric value
insuff
(2) If .75 kiloliter of gasoline were pumped into tank X, it would be filled to capacity.
nothing on present status..
we can say present = total - 0.75
insuff
combined
present volume = \(\frac{2}{3}\) of total capacity = \(\frac{2T}{3}\), which is 0.75 less than total
\(2\frac{T}{3} = T-0.75..............\frac{T}{3}=0.75................t=3*0.75\)
suff
C
(1) If 1/2 of the gasoline in tank X were pumped out, the tank would be filled to 1/3 of its capacity.
The values given are % of the total capacity and NO numeric value is given so insufficient
If \(\frac{1}{2}\) is pumped out, HALF will remain so \(\frac{1}{2} = \frac{1}{3}- of -Total\)
so present volume is \(2*\frac{1}{3} = \frac{2}{3}\)
but no numeric value
insuff
(2) If .75 kiloliter of gasoline were pumped into tank X, it would be filled to capacity.
nothing on present status..
we can say present = total - 0.75
insuff
combined
present volume = \(\frac{2}{3}\) of total capacity = \(\frac{2T}{3}\), which is 0.75 less than total
\(2\frac{T}{3} = T-0.75..............\frac{T}{3}=0.75................t=3*0.75\)
suff
C
General Discussion
If tank X contains only gasoline, how many kiloliters of gasoline are
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24 Dec 2018, 23:37
24 Dec 2018, 23:37
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Bunuel wrote:
If tank X contains only gasoline, how many kiloliters of gasoline are in tank X.
(1) If 1/2 of the gasoline in tank X were pumped out, the tank would be filled to 1/3 of its capacity.
(2) If .75 kiloliter of gasoline were pumped into tank X, it would be filled to capacity.
(1) If 1/2 of the gasoline in tank X were pumped out, the tank would be filled to 1/3 of its capacity.
(2) If .75 kiloliter of gasoline were pumped into tank X, it would be filled to capacity.
Let's define "x" as the # of kiloliters of gasoline in tank X.
Let's define "n" as the max capacity of tank X.
Statement 1:
x - x/2 = n/3 (in english: the current level of gasoline in tank x minus half the current amount will equal to 1/3 of the total capacity)
This is INSUFF because we have two variables
Statement 2:
x + 3/4 = n
Once again we have two variables, so this is INSUFF
Combined:
We have two equations so let's solve for a variable.
x - x/2 = n/3 -> 3x = 2n (cross multiply)
(x + 3/4 = n) * 2 = 2x + 6/4 = 2n
Subtract out "n" from above to get: x - 6/4 = 0
In other words the max capacity of tank X is 6/4 Kiloliters.
