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If w and z are positive is w/z < 1 ?

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If w and z are positive is w/z < 1 ? [#permalink]

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New post 26 Jul 2010, 00:58
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If w and z are positive is w/z < 1 ?

(1) w < 2
(2) z < 4
[Reveal] Spoiler: OA

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Re: arthmetic relation [#permalink]

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New post 26 Jul 2010, 01:27
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xmagedo wrote:
If w and Z are positive is W/Z<1 ?

1 w<2
2 Z<4


As given that \(z\) is positive we can safely multiply inequality \(\frac{w}{z}<1\) by it and we'll get \(w<z\). So the question becomes: is \(w<z\)?

(1) \(w<2\). No info about \(z\), not sufficient.
(2) \(z<4\). No info about \(w\), not sufficient.

(1)+(2) Still not sufficient, as \(w\) from the range \(0<w<2\) may or may not be more less than \(z\) from the range \(0<z<4\).

Answer: E.
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Re: If w and z are positive is w/z < 1 ? [#permalink]

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Hi Bunuel,
I agree with the answer. However, I noticed a typo in your explanation. "As given that z is positive we can safely multiply inequality by it and we'll get w>z. So the question becomes: is w>z?" When you multiply W/Z<1 by Z , you will get W<Z. Isn't that correct?

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Re: If w and z are positive is w/z < 1 ? [#permalink]

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New post 05 Feb 2017, 04:24
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anairamitch1804 wrote:
Bunuel wrote:
xmagedo wrote:
If w and Z are positive is W/Z<1 ?

1 w<2
2 Z<4


As given that \(z\) is positive we can safely multiply inequality \(\frac{w}{z}<1\) by it and we'll get \(w<z\). So the question becomes: is \(w<z\)?

(1) \(w<2\). No info about \(z\), not sufficient.
(2) \(z<4\). No info about \(w\), not sufficient.

(1)+(2) Still not sufficient, as \(w\) from the range \(0<w<2\) may or may not be more less than \(z\) from the range \(0<z<4\).

Answer: E.


Hello Bunuel,

If statement 1 would be "w<z" instead of "w<2" then also answer would be E?


In this case the answer would be A because the question asks exactly whether w < z.
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Re: arthmetic relation [#permalink]

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New post 26 Jul 2010, 14:51
1) w<2 (not suufficient,we dont have Z value)
2) Z<4 (not sufficient, we dont have W value)

By considering 2 statements together
Is W/Z<1
If consider different values for W,Z
W/Z<1 = 1/2 =0.5 makes the statement true
W/Z<1= 1.99/1=1.99 makes the statement false

so the answer is E

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Re: If w and Z are positive is W/Z<1 ? 1 w<2 2 Z<4 [#permalink]

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New post 24 Aug 2013, 21:46
OA is A ..
Can anyone tell why it is A?

Even I arrived at E.

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Re: If w and Z are positive is W/Z<1 ? 1 w<2 2 Z<4 [#permalink]

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New post 25 Aug 2013, 07:45

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Re: If w and z are positive is w/z < 1 ? [#permalink]

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New post 29 Aug 2013, 02:02
rumehta wrote:
Hi Bunuel,
I agree with the answer. However, I noticed a typo in your explanation. "As given that z is positive we can safely multiply inequality by it and we'll get w>z. So the question becomes: is w>z?" When you multiply W/Z<1 by Z , you will get W<Z. Isn't that correct?


Typo edited. Thank you.
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Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

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Re: If w and z are positive is w/z < 1 ? [#permalink]

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New post 17 Jan 2014, 05:44
xmagedo wrote:
If w and z are positive is w/z < 1 ?

(1) w < 2
(2) z < 4


Lets combine straight away:

w = 1 and z = 3 and w/z is less than 1

w = 1 and z = 0.5 and w/z is greater than 1

Hence E
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Re: If w and z are positive is w/z < 1 ? [#permalink]

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New post 04 Feb 2017, 23:16
Bunuel wrote:
xmagedo wrote:
If w and Z are positive is W/Z<1 ?

1 w<2
2 Z<4


As given that \(z\) is positive we can safely multiply inequality \(\frac{w}{z}<1\) by it and we'll get \(w<z\). So the question becomes: is \(w<z\)?

(1) \(w<2\). No info about \(z\), not sufficient.
(2) \(z<4\). No info about \(w\), not sufficient.

(1)+(2) Still not sufficient, as \(w\) from the range \(0<w<2\) may or may not be more less than \(z\) from the range \(0<z<4\).

Answer: E.


Hello Bunuel,

If statement 1 would be "w<z" instead of "w<2" then also answer would be E?
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Re: If w and z are positive is w/z < 1 ?   [#permalink] 04 Feb 2017, 23:16
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