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26 Jul 2017, 09:05
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Difficulty:
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78% (01:11) correct
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If x > 0, what is the value of x ?
(1) \(x^3 – x = 0\)
(2) \(\sqrt[3]{x} - x = 0\)
(DS17543)
(1) \(x^3 – x = 0\)
(2) \(\sqrt[3]{x} - x = 0\)
(DS17543)
26 Jul 2017, 09:19
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If x > 0, what is the value of x ?
(1) \(x^3 – x = 0\). Since x is not 0, we can safely reduce by x:
\(x^2 - 1 = 0\)
\(x^2 = 1\)
\(x = 1\) or \(x = -1\) (discard since \(x > 0\)).
So, \(x = 1\) only. Sufficient.
(2) \(\sqrt[3]{x} - x = 0\)
\(\sqrt[3]{x} =x\)
\(x = x^3\)
\(x^3 – x = 0\).
The same as in (1). Sufficient.
Answer: D.
(1) \(x^3 – x = 0\). Since x is not 0, we can safely reduce by x:
\(x^2 - 1 = 0\)
\(x^2 = 1\)
\(x = 1\) or \(x = -1\) (discard since \(x > 0\)).
So, \(x = 1\) only. Sufficient.
(2) \(\sqrt[3]{x} - x = 0\)
\(\sqrt[3]{x} =x\)
\(x = x^3\)
\(x^3 – x = 0\).
The same as in (1). Sufficient.
Answer: D.
General Discussion
07 Dec 2017, 11:03
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Dear Bunuel can you please clarify "^3√x=x, then x=x^3" how the interchange occurred? and I had x=1 in the statement 1 which made that sufficient, but what value do Statement 2 has to make it sufficient? Not getting this part in statement 2 "x^3–x=0. The same as in (1). Sufficient".
