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If x!=0, what is the value of (x^p/x^q)^2 ? (1) p is

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dreambeliever
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If x!=0, what is the value of (x^p/x^q)^2 ? (1) p is [#permalink] New post   10 Jun 2011, 07:24
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A
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If x!=0, what is the value of \((x^p/x^q)^2\)?

(1) p is a multiple of q.
(2) q is a multiple of p.

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Re: If x!=0, what is the value of (x^p/x^q)^2 ? (1) p is [#permalink] New post   10 Jun 2011, 09:58
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sudhir18n wrote:
I also think its E. Same reasoning as subhash.
BTW . which numbers factorial is '0'? Isnt X!=0 wrong at first instance?


!= means NOT EQUAL TO. It is not factorial.

\(x \ne 0\)
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Re: If x!=0, what is the value of (x^p/x^q)^2 ? (1) p is [#permalink] New post   10 Jun 2011, 10:52
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This question is not well designed. For either statement to talk about multiples in the first place, the stem needs to tell us that p and q are integers. *Real* GMAT questions about multiples and divisibility always only deal with *positive* integers. Because of that, I think it's reasonable to assume p and q are positive integers here and that the question designer was just too careless to mention that fact. If that's the case, then if p is a multiple of q and q is a multiple of p, it must be that p=q, and the information is sufficient, so the answer is C.

If, on the other hand, p or q could be negative, then the answer is E, but that's testing a technicality that is always irrelevant on real GMAT multiples questions.

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Re: If x!=0, what is the value of (x^p/x^q)^2 ? (1) p is [#permalink] New post   10 Jun 2011, 07:36
I think the answer is C.

Both options individually tell me that there will be some power of x left over either in the numerator or denominator. So that eliminates A,B and D

Taking both options together, I'd have to say that both powers are 1 and therefore the value of x is 1.
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Re: If x!=0, what is the value of (x^p/x^q)^2 ? (1) p is [#permalink] New post   10 Jun 2011, 08:39
What if p =-q? They'll still be multiples of each other but the ans will not be 1.

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Re: If x!=0, what is the value of (x^p/x^q)^2 ? (1) p is [#permalink] New post   10 Jun 2011, 08:50
dreambeliever wrote:
What if p =-q? They'll still be multiples of each other but the ans will not be 1.

Posted from my mobile device


Hmm.. i guess you're right.. where did you source this question?
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Re: If x!=0, what is the value of (x^p/x^q)^2 ? (1) p is [#permalink] New post   10 Jun 2011, 08:59
I think the answer is E. If p = q = 0, then the result is 1.

If p = -1/1 and q = -1/1, then the answer differs, and hence we can't determine the same.
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Re: If x!=0, what is the value of (x^p/x^q)^2 ? (1) p is [#permalink] New post   10 Jun 2011, 09:40
Consider both the cases
1. p is multiple of q ie p=2q
2. q is multiple of p ie q=2p

In both the cases as we dont know the actual value either p or q and X we wont be able to determine the value so I think answer is E
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Re: If x!=0, what is the value of (x^p/x^q)^2 ? (1) p is [#permalink] New post   10 Jun 2011, 09:55
I also think its E. Same reasoning as subhash.
BTW . which numbers factorial is '0'? Isnt X!=0 wrong at first instance?
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Re: If x!=0, what is the value of (x^p/x^q)^2 ? (1) p is [#permalink]
10 Jun 2011, 09:55
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