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WE: Supply Chain Management (Energy and Utilities)
Re: If x^(1/2) is an integer and xy^2 = 36, how many values are possible
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30 Aug 2018, 23:58
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Bunuel wrote:
If \(\sqrt{x}\) is an integer and \(xy^2 = 36\), how many values are possible for the integer y?
(A) Two (B) Three (C) Four (D) Six (E) Eight
+1 for (E).
Given,\(xy^2 = 36\) Since x is a perfect square , so it could be : 1, 4, 9 and 36 So, \(y^2\): 36,9,4 and 1 hence, possible values of y:+6,-6,+3,-3,+2,-2,+1,-1 (both faces of polarities)
SO, 8 values are possible for the integer y.
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Re: If x^(1/2) is an integer and xy^2 = 36, how many values are possible
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31 Aug 2018, 00:47
Bunuel wrote:
If \(\sqrt{x}\) is an integer and \(xy^2 = 36\), how many values are possible for the integer y?
(A) Two (B) Three (C) Four (D) Six (E) Eight
The possible factors of 36 are 1x36;2x18;3x12;4x9;6x6 Since \(\sqrt{x}\) is an integer, x can be 1, 4 ,9, 36 Possible values of y corresponding to x : ±6, ±3, ±2, ±1 8 values are possible. Answer E.
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