Last visit was: 26 Apr 2024, 07:37 It is currently 26 Apr 2024, 07:37

Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
SORT BY:
Date
Tags:
Show Tags
Hide Tags
GMAT Club Legend
GMAT Club Legend
Joined: 12 Sep 2015
Posts: 6818
Own Kudos [?]: 29938 [17]
Given Kudos: 799
Location: Canada
Send PM
RC & DI Moderator
Joined: 02 Aug 2009
Status:Math and DI Expert
Posts: 11181
Own Kudos [?]: 31950 [4]
Given Kudos: 291
Send PM
GMAT Club Legend
GMAT Club Legend
Joined: 12 Sep 2015
Posts: 6818
Own Kudos [?]: 29938 [3]
Given Kudos: 799
Location: Canada
Send PM
GMAT Club Legend
GMAT Club Legend
Joined: 12 Sep 2015
Posts: 6818
Own Kudos [?]: 29938 [0]
Given Kudos: 799
Location: Canada
Send PM
Re: If x and y are different positive integers, which of the following COU [#permalink]
Expert Reply
Top Contributor
chetan2u wrote:
If x and y are different positive integers, which of the following COULD be true:

i) When x is divided by y, the remainder is 2x
Remainder cannot be > than the dividend ... So not possible

ii) When x is divided by 2y, the remainder is y
when x =3y or x=5 y or x=7y and so on, this will be true

iii) When (2x + y) is divided by (x + y), the remainder is y
2x+y=x+x+y will leave a remainder of x when divided by x+y..
But it is given as y, this means x=y ..
But it is given that x and y are distinct so not possible

Only (ii)

B


Hi chetan2u,

I thought I'd mention that testing only one pair of values for x and y isn't enough to say statement iii cannot be true.
If that were the case, we could also conclude that statement ii is not true, because if we test the first possible value of x, we get x = y, which isn't allowed.

Cheers,
Brent
RC & DI Moderator
Joined: 02 Aug 2009
Status:Math and DI Expert
Posts: 11181
Own Kudos [?]: 31950 [0]
Given Kudos: 291
Send PM
If x and y are different positive integers, which of the following COU [#permalink]
Expert Reply
GMATPrepNow wrote:
chetan2u wrote:
If x and y are different positive integers, which of the following COULD be true:

i) When x is divided by y, the remainder is 2x
Remainder cannot be > than the dividend ... So not possible

ii) When x is divided by 2y, the remainder is y
when x =3y or x=5 y or x=7y and so on, this will be true

iii) When (2x + y) is divided by (x + y), the remainder is y
2x+y=x+x+y will leave a remainder of x when divided by x+y..
But it is given as y, this means x=y ..
But it is given that x and y are distinct so not possible

Only (ii)

B


Hi chetan2u,

I thought I'd mention that testing only one pair of values for x and y isn't enough to say statement iii cannot be true.
If that were the case, we could also conclude that statement ii is not true, because if we test the first possible value of x, we get x = y, which isn't allowed.

Cheers,
Brent



Hi GMATPrepNow,

I am not saying that iii is not possible because of one example, rather I have not taken any examples.
But iii is possible only when x=y and I have derived it.
I have just rewritten 2x+y as X+X+y.
When I divide this by X+y....(X+X+y)/(X+y)=X/(X+y) + (X+y)/(X+y), so clearly remainder is x as X+y /X+y will leave 0 as remainder...
But choice iii mentions y as a remainder in this case, so we derived X and it is given en it is equal to y... So x=y, but both are distinct so not possible.

So I didn't take any examples, but proved it that X has to be equal to y for iii to be true
GMAT Club Legend
GMAT Club Legend
Joined: 12 Sep 2015
Posts: 6818
Own Kudos [?]: 29938 [0]
Given Kudos: 799
Location: Canada
Send PM
Re: If x and y are different positive integers, which of the following COU [#permalink]
Expert Reply
Top Contributor
chetan2u wrote:

I am not saying that iii is not possible because of one example, rather I have not taken any examples.
But iii is possible only when x=y and I have derived it.
I have just rewritten 2x+y as X+X+y.
When I divide this by X+y....(X+X+y)/(X+y)=X/(X+y) + (X+y)/(X+y), so clearly remainder is x as X+y /X+y will leave 0 as remainder...
But choice iii mentions y as a remainder in this case, so we derived X and it is given en it is equal to y... So x=y, but both are distinct so not possible.

So I didn't take any examples, but proved it that X has to be equal to y for iii to be true


You're absolutely right!
I misread your solution. Sorry about that.

Cheers,
Brent
Target Test Prep Representative
Joined: 14 Oct 2015
Status:Founder & CEO
Affiliations: Target Test Prep
Posts: 18761
Own Kudos [?]: 22056 [0]
Given Kudos: 283
Location: United States (CA)
Send PM
Re: If x and y are different positive integers, which of the following COU [#permalink]
Expert Reply
GMATPrepNow wrote:
If x and y are different positive integers, which of the following COULD be true:

i) When x is divided by y, the remainder is 2x
ii) When x is divided by 2y, the remainder is y
iii) When (2x + y) is divided by (x + y), the remainder is y

A) i only
B) ii only
C) iii only
D) i & ii only
E) ii & iii only


Since the remainder can’t be greater than the dividend or the divisor, we see that statement (i) is not true.

If x = 9 and y = 3, we see that the remainder is 3 when 9 is divided by 6. So statement (ii) could be true.

Since (2x + y)/(x + y) = (x + y + x)/(x + y) = (x + y)/(x + y) + x/(x + y) = 1 + x/(x + y), we see that the remainder must be x. However, since x and y are different positive integers, then the remainder can’t be y. We see that statement (iii) is not true.

Answer: B
Manager
Manager
Joined: 29 May 2017
Posts: 154
Own Kudos [?]: 19 [0]
Given Kudos: 63
Location: Pakistan
Concentration: Social Entrepreneurship, Sustainability
Send PM
Re: If x and y are different positive integers, which of the following COU [#permalink]
GMATPrepNow wrote:
GMATPrepNow wrote:
If x and y are different positive integers, which of the following COULD be true:

i) When x is divided by y, the remainder is 2x
ii) When x is divided by 2y, the remainder is y
iii) When (2x + y) is divided by (x + y), the remainder is y

A) i only
B) ii only
C) iii only
D) i & ii only
E) ii & iii only

ASIDE: Many Integer Properties questions can be solved by identifying values that satisfy some given conditions. This question is intended to strengthen that skill.

Related question: https://gmatclub.com/forum/if-x-and-y-a ... 80118.html


i) When x is divided by y, the remainder is 2x
The remainder cannot be greater than the dividend (the number we're dividing)
For example, it CANNOT be the case that 17 divided by 5 leaves a remainder of 34
Statement i can never be true
Check the answer choices. . . . ELIMINATE A and D

ii) When x is divided by 2y, the remainder is y
Nice rule: If N divided by D leaves remainder R, then the possible values of N are R, R+D, R+2D, R+3D,. . . etc.
For example, if k divided by 5 leaves a remainder of 1, then the possible values of k are: 1, 1+5, 1+(2)(5), 1+(3)(5), 1+(4)(5), . . . etc.

So, some possible values of x are: y, y + 2y, y + 4y, y + 6y, . . . etc
Let's TEST the 1st option: x = y. No good.
The question tells us that x and y are different

So, let's TEST the 2nd option: x = y + 2y = 3y
So, how about x = 15 and y = 5
When we plug those values into statement ii, we get: When 15 is divided by 10, the remainder is 5
PERFECT!
Statement ii CAN be true.
Check the answer choices. . . . ELIMINATE C

iii) When (2x + y) is divided by (x + y), the remainder is y
When we apply the above rule, we get....
Some possible values of (2x + y) are: y, y + (x + y), y + 2(x + y), y + 3(x + y), . . . etc

Let's TEST the 1st option: (2x + y) = y.
Solve to get x = 0
No good. We're told x is POSITIVE

Let's TEST the 2nd option: (2x + y) = y + (x + y)
Solve to get: x = y
No good. The question tells us that x and y are different

Let's TEST the 3rd option: (2x + y) = y + 2(x + y)
Solve to get: y = 0
No good. We're told y is POSITIVE

Let's TEST the 4th option: (2x + y) = y + 3(x + y)
Solve to get: x = -3y
No good. If y is POSITIVE, then that means x is NEGATIVE, but we're told x is POSITIVE

Let's TEST the 5th option: (2x + y) = y + 4(x + y)
Solve to get: 2x = -4y
No good. If y is POSITIVE, then that means x is NEGATIVE, but we're told x is POSITIVE

At this point, we should recognize that, if we keep going, we'll keep running into the same problem where either x or y is NEGATIVE (which contradicts the given information.
So, statement iii can never be true

Answer: B

Cheers,
Brent

RELATED VIDEO FROM OUR COURSE


Hi.....

this is in regards to Option III

if r = y, clearly this means r<x+y
so III can be true?

can you tell me where i am going wrong?
GMAT Club Legend
GMAT Club Legend
Joined: 12 Sep 2015
Posts: 6818
Own Kudos [?]: 29938 [0]
Given Kudos: 799
Location: Canada
Send PM
Re: If x and y are different positive integers, which of the following COU [#permalink]
Expert Reply
Top Contributor
Mansoor50 wrote:

Hi.....

this is in regards to Option III

if r = y, clearly this means r<x+y
so III can be true?

can you tell me where i am going wrong?


Just because the remainder (y) is less than the dividend (x+y) doesn't mean that the division in statement iii is possible.

Here's an example: When 20 is divided by 8, is it possible for the remainder to be 3?
No.
So. even though the proposed remainder (3) is less than the dividend (8), it is not possible for the remainder to be 3. When 20 is divided by 8, the remainder is 4

Cheers,
Brent
Manager
Manager
Joined: 29 May 2017
Posts: 154
Own Kudos [?]: 19 [0]
Given Kudos: 63
Location: Pakistan
Concentration: Social Entrepreneurship, Sustainability
Send PM
Re: If x and y are different positive integers, which of the following COU [#permalink]
GMATPrepNow wrote:
Mansoor50 wrote:

Hi.....

this is in regards to Option III

if r = y, clearly this means r<x+y
so III can be true?

can you tell me where i am going wrong?


Just because the remainder (y) is less than the dividend (x+y) doesn't mean that the division in statement iii is possible.

Here's an example: When 20 is divided by 8, is it possible for the remainder to be 3?
No.
So. even though the proposed remainder (3) is less than the dividend (8), it is not possible for the remainder to be 3. When 20 is divided by 8, the remainder is 4

Cheers,
Brent


Thank you!!
Manager
Manager
Joined: 29 May 2017
Posts: 154
Own Kudos [?]: 19 [0]
Given Kudos: 63
Location: Pakistan
Concentration: Social Entrepreneurship, Sustainability
Send PM
Re: If x and y are different positive integers, which of the following COU [#permalink]
GMATPrepNow wrote:
GMATPrepNow wrote:
If x and y are different positive integers, which of the following COULD be true:

i) When x is divided by y, the remainder is 2x
ii) When x is divided by 2y, the remainder is y
iii) When (2x + y) is divided by (x + y), the remainder is y

A) i only
B) ii only
C) iii only
D) i & ii only
E) ii & iii only

ASIDE: Many Integer Properties questions can be solved by identifying values that satisfy some given conditions. This question is intended to strengthen that skill.

Related question: https://gmatclub.com/forum/if-x-and-y-a ... 80118.html


i) When x is divided by y, the remainder is 2x
The remainder cannot be greater than the dividend (the number we're dividing)
For example, it CANNOT be the case that 17 divided by 5 leaves a remainder of 34
Statement i can never be true
Check the answer choices. . . . ELIMINATE A and D

ii) When x is divided by 2y, the remainder is y
Nice rule: If N divided by D leaves remainder R, then the possible values of N are R, R+D, R+2D, R+3D,. . . etc.
For example, if k divided by 5 leaves a remainder of 1, then the possible values of k are: 1, 1+5, 1+(2)(5), 1+(3)(5), 1+(4)(5), . . . etc.

So, some possible values of x are: y, y + 2y, y + 4y, y + 6y, . . . etc
Let's TEST the 1st option: x = y. No good.
The question tells us that x and y are different

So, let's TEST the 2nd option: x = y + 2y = 3y
So, how about x = 15 and y = 5
When we plug those values into statement ii, we get: When 15 is divided by 10, the remainder is 5
PERFECT!
Statement ii CAN be true.
Check the answer choices. . . . ELIMINATE C

iii) When (2x + y) is divided by (x + y), the remainder is y
When we apply the above rule, we get....
Some possible values of (2x + y) are: y, y + (x + y), y + 2(x + y), y + 3(x + y), . . . etc

Let's TEST the 1st option: (2x + y) = y.
Solve to get x = 0
No good. We're told x is POSITIVE

Let's TEST the 2nd option: (2x + y) = y + (x + y)
Solve to get: x = y
No good. The question tells us that x and y are different

Let's TEST the 3rd option: (2x + y) = y + 2(x + y)
Solve to get: y = 0
No good. We're told y is POSITIVE

Let's TEST the 4th option: (2x + y) = y + 3(x + y)
Solve to get: x = -3y
No good. If y is POSITIVE, then that means x is NEGATIVE, but we're told x is POSITIVE

Let's TEST the 5th option: (2x + y) = y + 4(x + y)
Solve to get: 2x = -4y
No good. If y is POSITIVE, then that means x is NEGATIVE, but we're told x is POSITIVE

At this point, we should recognize that, if we keep going, we'll keep running into the same problem where either x or y is NEGATIVE (which contradicts the given information.
So, statement iii can never be true

Answer: B

Cheers,
Brent

RELATED VIDEO FROM OUR COURSE


Hi...I went over your solution at least 4 times and now i can say i get it..finally!!!
kudos..:)
Manager
Manager
Joined: 29 May 2017
Posts: 154
Own Kudos [?]: 19 [0]
Given Kudos: 63
Location: Pakistan
Concentration: Social Entrepreneurship, Sustainability
Send PM
Re: If x and y are different positive integers, which of the following COU [#permalink]
another algebra approach:

1. x = ky + 2x ---> -x=ky ..... since x and y are positive integers..not possible

2. x = 2ky + 2y ----> x = (2k + 1)y ..... this is possible since x/2y --> (2k + 1)y/2y ---> (2k + 1)/2

3. (2x +y)/(x+y) --> (2x +y)=(x+y)k + y ---> x(2-k)=ky..... this can not be for any values of k

so B
Manager
Manager
Joined: 22 Jan 2020
Posts: 69
Own Kudos [?]: 13 [0]
Given Kudos: 304
GMAT 1: 730 Q43 V42
Send PM
If x and y are different positive integers, which of the following COU [#permalink]
Quote:

iii) When (2x + y) is divided by (x + y), the remainder is y
2x+y=x+x+y will leave a remainder of x when divided by x+y..
But it is given as y, this means x=y ..
But it is given that x and y are distinct so not possible


B


chetan2u


is this description of 2x+y / x + y = x as a remainder related to the binomial theorem?

it seems like it is
User avatar
Non-Human User
Joined: 09 Sep 2013
Posts: 32685
Own Kudos [?]: 822 [0]
Given Kudos: 0
Send PM
Re: If x and y are different positive integers, which of the following COU [#permalink]
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
GMAT Club Bot
Re: If x and y are different positive integers, which of the following COU [#permalink]
Moderators:
Math Expert
92933 posts
Senior Moderator - Masters Forum
3137 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne